Вопрос:

Вычислите: а) \(\frac{1}{4}+\frac{2}{4}\); б) \(\frac{7}{12}-\frac{2}{12}\); в) \(\frac{3}{9}+\frac{5}{9}\); г) \(\frac{6}{8}-\frac{5}{8}\); д) \(\frac{4}{11}+\frac{6}{11}\).

Ответ:

  1. \(\frac{1}{4}+\frac{2}{4}=\frac{1+2}{4}=\frac{3}{4}\).
  2. \(\frac{7}{12}-\frac{2}{12}=\frac{7-2}{12}=\frac{5}{12}\).
  3. \(\frac{3}{9}+\frac{5}{9}=\frac{3+5}{9}=\frac{8}{9}\).
  4. \(\frac{6}{8}-\frac{5}{8}=\frac{6-5}{8}=\frac{1}{8}\).
  5. \(\frac{4}{11}+\frac{6}{11}=\frac{4+6}{11}=\frac{10}{11}\).

Ответ: а) \(\frac{3}{4}\); б) \(\frac{5}{12}\); в) \(\frac{8}{9}\); г) \(\frac{1}{8}\); д) \(\frac{10}{11}\).