a) \[\frac{11}{12} + \frac{5}{6} + \frac{7}{12} = \frac{11}{12} + \frac{7}{12} + \frac{5}{6} = \frac{11}{12} + \frac{7}{12} + \frac{10}{12} = \frac{18}{12} + \frac{10}{12} = \frac{28}{12} = \frac{14}{6} = \frac{7}{3} = 2\frac{1}{3}\]
б) \[\frac{3}{8} + \frac{11}{24} + \frac{13}{24} = \frac{3}{8} + (\frac{11}{24} + \frac{13}{24}) = \frac{3}{8} + \frac{24}{24} = \frac{3}{8} + 1 = 1\frac{3}{8}\]
a) \[(\frac{7}{15} + \frac{3}{5}) - \frac{2}{15} = \frac{7}{15} + \frac{9}{15} - \frac{2}{15} = \frac{16}{15} - \frac{2}{15} = \frac{14}{15}\]
б) \[\frac{17}{28} - (\frac{1}{4} + \frac{9}{28}) = \frac{17}{28} - \frac{7}{28} - \frac{9}{28} = \frac{10}{28} - \frac{9}{28} = \frac{1}{28}\]
Ответ: a) \[2\frac{1}{3}\]; б) \[1\frac{3}{8}\]; 5. a) \[\frac{14}{15}\]; б) \[\frac{1}{28}\]