\[\left(2.5-1\frac{1}{3}\right)\cdot6+1.2:0.4=\left(\frac{5}{2}-\frac{4}{3}\right)\cdot6+3\]
\[\frac{5}{2}-\frac{4}{3}=\frac{15-8}{6}=\frac{7}{6},\qquad \frac{7}{6}\cdot6+3=7+3=10.\]
Ответ: 10.