Вопрос:

Вычислите sint u cost, если: 13.1. a) t = 0; =- π 6) t =; 2 4 5π 5π 3.2. a) t = 6) t = 0; 6 13π 8π 3.3. a) = 13; 6) = -8; t =-- 3 3π. B) t = ; 2 7π B) t = ; 6 B) t = 23; 6 r) t = π. r) t = 9π 4 г) t = 11π 3 t 6 Вычислите: π π π 4. a) sin -- + cos + cos - ; 4 3 6 π π π 6) cos- π • COS • COS B) sin r) sin 6 π -- 2 π sin 4 4 3 • COS -; 2' cos (-π) + sin η3π ; 2 π π sin • sin 3 2

Смотреть решения всех заданий с листа

Ответ:

Привет! Сейчас помогу разобраться с тригонометрическими функциями. Будет интересно!

13.1. а) t = 0

  • sin(0) = 0
  • cos(0) = 1

б) t = \(\frac{\pi}{2}\)

  • sin(\( \frac{\pi}{2} \)) = 1
  • cos(\( \frac{\pi}{2} \)) = 0

в) t = \(\frac{3\pi}{2}\)

  • sin(\( \frac{3\pi}{2} \)) = -1
  • cos(\( \frac{3\pi}{2} \)) = 0

г) t = \(\pi\)

  • sin(\( \pi \)) = 0
  • cos(\( \pi \)) = -1

3.2. а) t = \(\frac{5\pi}{6}\)

  • sin(\( \frac{5\pi}{6} \)) = \(\frac{1}{2}\)
  • cos(\( \frac{5\pi}{6} \)) = \(-\frac{\sqrt{3}}{2}\)

б) t = \(\frac{5\pi}{4}\)

  • sin(\( \frac{5\pi}{4} \)) = \(-\frac{\sqrt{2}}{2}\)
  • cos(\( \frac{5\pi}{4} \)) = \(-\frac{\sqrt{2}}{2}\)

в) t = \(\frac{7\pi}{6}\)

  • sin(\( \frac{7\pi}{6} \)) = \(-\frac{1}{2}\)
  • cos(\( \frac{7\pi}{6} \)) = \(-\frac{\sqrt{3}}{2}\)

г) t = \(\frac{9\pi}{4}\)

  • sin(\( \frac{9\pi}{4} \)) = sin(\( 2\pi + \frac{\pi}{4} \)) = sin(\( \frac{\pi}{4} \)) = \(\frac{\sqrt{2}}{2}\)
  • cos(\( \frac{9\pi}{4} \)) = cos(\( 2\pi + \frac{\pi}{4} \)) = cos(\( \frac{\pi}{4} \)) = \(\frac{\sqrt{2}}{2}\)

3.3. а) t = \(\frac{13\pi}{6}\)

  • sin(\( \frac{13\pi}{6} \)) = sin(\( 2\pi + \frac{\pi}{6} \)) = sin(\( \frac{\pi}{6} \)) = \(\frac{1}{2}\)
  • cos(\( \frac{13\pi}{6} \)) = cos(\( 2\pi + \frac{\pi}{6} \)) = cos(\( \frac{\pi}{6} \)) = \(\frac{\sqrt{3}}{2}\)

б) t = \(-\frac{8\pi}{3}\)

  • sin(\( -\frac{8\pi}{3} \)) = sin(\( -2\pi - \frac{2\pi}{3} \)) = sin(\( -\frac{2\pi}{3} \)) = \(-\frac{\sqrt{3}}{2}\)
  • cos(\( -\frac{8\pi}{3} \)) = cos(\( -2\pi - \frac{2\pi}{3} \)) = cos(\( -\frac{2\pi}{3} \)) = \(-\frac{1}{2}\)

в) t = \(\frac{23\pi}{6}\)

  • sin(\( \frac{23\pi}{6} \)) = sin(\( 4\pi - \frac{\pi}{6} \)) = sin(\( -\frac{\pi}{6} \)) = \(-\frac{1}{2}\)
  • cos(\( \frac{23\pi}{6} \)) = cos(\( 4\pi - \frac{\pi}{6} \)) = cos(\( -\frac{\pi}{6} \)) = \(\frac{\sqrt{3}}{2}\)

г) t = \(-\frac{11\pi}{3}\)

  • sin(\( -\frac{11\pi}{3} \)) = sin(\( -4\pi + \frac{\pi}{3} \)) = sin(\( \frac{\pi}{3} \)) = \(\frac{\sqrt{3}}{2}\)
  • cos(\( -\frac{11\pi}{3} \)) = cos(\( -4\pi + \frac{\pi}{3} \)) = cos(\( \frac{\pi}{3} \)) = \(\frac{1}{2}\)

4. a)

sin(\( -\frac{\pi}{4} \)) + cos(\( \frac{\pi}{3} \)) + cos(\( -\frac{\pi}{6} \)) = \(-\frac{\sqrt{2}}{2}\) + \(\frac{1}{2}\) + \(\frac{\sqrt{3}}{2}\)

б)

cos(\( \frac{\pi}{6} \)) * cos(\( \frac{\pi}{4} \)) * cos(\( \frac{\pi}{3} \)) * cos(\( \frac{\pi}{2} \)) = \(\frac{\sqrt{3}}{2}\) * \(\frac{\sqrt{2}}{2}\) * \(\frac{1}{2}\) * 0 = 0

в)

sin(\( -\frac{\pi}{2} \)) - cos(\( -\pi \)) + sin(\( -\frac{3\pi}{2} \)) = -1 - (-1) + 1 = 1

г)

sin(\( \frac{\pi}{6} \)) * sin(\( \frac{\pi}{4} \)) * sin(\( \frac{\pi}{3} \)) * sin(\( \frac{\pi}{2} \)) = \(\frac{1}{2}\) * \(\frac{\sqrt{2}}{2}\) * \(\frac{\sqrt{3}}{2}\) * 1 = \(\frac{\sqrt{6}}{8}\)

ГДЗ по фото 📸
Подать жалобу Правообладателю