Привет! Сейчас помогу разобраться с тригонометрическими функциями. Будет интересно!
13.1. а) t = 0
б) t = \(\frac{\pi}{2}\)
- sin(\( \frac{\pi}{2} \)) = 1
- cos(\( \frac{\pi}{2} \)) = 0
в) t = \(\frac{3\pi}{2}\)
- sin(\( \frac{3\pi}{2} \)) = -1
- cos(\( \frac{3\pi}{2} \)) = 0
г) t = \(\pi\)
- sin(\( \pi \)) = 0
- cos(\( \pi \)) = -1
3.2. а) t = \(\frac{5\pi}{6}\)
- sin(\( \frac{5\pi}{6} \)) = \(\frac{1}{2}\)
- cos(\( \frac{5\pi}{6} \)) = \(-\frac{\sqrt{3}}{2}\)
б) t = \(\frac{5\pi}{4}\)
- sin(\( \frac{5\pi}{4} \)) = \(-\frac{\sqrt{2}}{2}\)
- cos(\( \frac{5\pi}{4} \)) = \(-\frac{\sqrt{2}}{2}\)
в) t = \(\frac{7\pi}{6}\)
- sin(\( \frac{7\pi}{6} \)) = \(-\frac{1}{2}\)
- cos(\( \frac{7\pi}{6} \)) = \(-\frac{\sqrt{3}}{2}\)
г) t = \(\frac{9\pi}{4}\)
- sin(\( \frac{9\pi}{4} \)) = sin(\( 2\pi + \frac{\pi}{4} \)) = sin(\( \frac{\pi}{4} \)) = \(\frac{\sqrt{2}}{2}\)
- cos(\( \frac{9\pi}{4} \)) = cos(\( 2\pi + \frac{\pi}{4} \)) = cos(\( \frac{\pi}{4} \)) = \(\frac{\sqrt{2}}{2}\)
3.3. а) t = \(\frac{13\pi}{6}\)
- sin(\( \frac{13\pi}{6} \)) = sin(\( 2\pi + \frac{\pi}{6} \)) = sin(\( \frac{\pi}{6} \)) = \(\frac{1}{2}\)
- cos(\( \frac{13\pi}{6} \)) = cos(\( 2\pi + \frac{\pi}{6} \)) = cos(\( \frac{\pi}{6} \)) = \(\frac{\sqrt{3}}{2}\)
б) t = \(-\frac{8\pi}{3}\)
- sin(\( -\frac{8\pi}{3} \)) = sin(\( -2\pi - \frac{2\pi}{3} \)) = sin(\( -\frac{2\pi}{3} \)) = \(-\frac{\sqrt{3}}{2}\)
- cos(\( -\frac{8\pi}{3} \)) = cos(\( -2\pi - \frac{2\pi}{3} \)) = cos(\( -\frac{2\pi}{3} \)) = \(-\frac{1}{2}\)
в) t = \(\frac{23\pi}{6}\)
- sin(\( \frac{23\pi}{6} \)) = sin(\( 4\pi - \frac{\pi}{6} \)) = sin(\( -\frac{\pi}{6} \)) = \(-\frac{1}{2}\)
- cos(\( \frac{23\pi}{6} \)) = cos(\( 4\pi - \frac{\pi}{6} \)) = cos(\( -\frac{\pi}{6} \)) = \(\frac{\sqrt{3}}{2}\)
г) t = \(-\frac{11\pi}{3}\)
- sin(\( -\frac{11\pi}{3} \)) = sin(\( -4\pi + \frac{\pi}{3} \)) = sin(\( \frac{\pi}{3} \)) = \(\frac{\sqrt{3}}{2}\)
- cos(\( -\frac{11\pi}{3} \)) = cos(\( -4\pi + \frac{\pi}{3} \)) = cos(\( \frac{\pi}{3} \)) = \(\frac{1}{2}\)
4. a)
sin(\( -\frac{\pi}{4} \)) + cos(\( \frac{\pi}{3} \)) + cos(\( -\frac{\pi}{6} \)) = \(-\frac{\sqrt{2}}{2}\) + \(\frac{1}{2}\) + \(\frac{\sqrt{3}}{2}\)
б)
cos(\( \frac{\pi}{6} \)) * cos(\( \frac{\pi}{4} \)) * cos(\( \frac{\pi}{3} \)) * cos(\( \frac{\pi}{2} \)) = \(\frac{\sqrt{3}}{2}\) * \(\frac{\sqrt{2}}{2}\) * \(\frac{1}{2}\) * 0 = 0
в)
sin(\( -\frac{\pi}{2} \)) - cos(\( -\pi \)) + sin(\( -\frac{3\pi}{2} \)) = -1 - (-1) + 1 = 1
г)
sin(\( \frac{\pi}{6} \)) * sin(\( \frac{\pi}{4} \)) * sin(\( \frac{\pi}{3} \)) * sin(\( \frac{\pi}{2} \)) = \(\frac{1}{2}\) * \(\frac{\sqrt{2}}{2}\) * \(\frac{\sqrt{3}}{2}\) * 1 = \(\frac{\sqrt{6}}{8}\)