Ответ:
а)
\(12\frac{1}{3}-11\frac{1}{4}=1\frac{1}{12}\),
\(14-9\frac{8}{15}=4\frac{7}{15}\).
\[1\frac{1}{12}+4\frac{7}{15}=5+\frac{5}{60}+\frac{28}{60}=5\frac{11}{20}.\]
б)
\(15-12\frac{5}{8}=2\frac{3}{8}\),
\(13\frac{1}{2}-11\frac{2}{9}=2\frac{1}{2}-\frac{2}{9}=\frac{41}{18}\).
\[2\frac{3}{8}-\frac{41}{18}=\frac{19}{8}-\frac{41}{18}=\frac{171-164}{72}=\frac{7}{72}.\]
в)
\[14\frac{2}{3}-5\frac{5}{9}=\frac{82}{9},\quad 3\frac{7}{8}+4\frac{5}{6}=\frac{209}{24},\quad 10\frac{3}{4}-4\frac{4}{9}=\frac{227}{36}.\]
\[\frac{82}{9}-\frac{209}{24}+\frac{227}{36}=\frac{656-627+454}{72}=\frac{483}{72}=6\frac{17}{24}.\]
г)
\[14\frac{5}{7}-14=\frac{5}{7},\quad 30-29\frac{5}{7}=\frac{2}{7},\quad 3\frac{1}{7}-\frac{23}{28}=\frac{65}{28}.\]
\[\frac{5}{7}+\frac{2}{7}+\frac{65}{28}=1+\frac{65}{28}=3\frac{9}{28}.\]
Ответ: а) \(5\frac{11}{20}\); б) \(\frac{7}{72}\); в) \(6\frac{17}{24}\); г) \(3\frac{9}{28}\).
