Вычислите значения выражений: а) (-15,64 : 4 3/5 + 7,1) · 2 2/5; б) (0,4 − 11/15) · 1 2/7 − (7/18 − 0,5) : 1 1/6; в) 0,8 : ((37,12 − 5,6 · 0,14)/(1,21 + 3,4 + 0,35)); г) (2,17 · 3,7 − 1,83 · 2,3) : 19,1; д) 5 4/19 · 3 4/7 − 1 15/19 : 7/25 − 1 2/3; е) ((3 1/3 − 2 2/3) · 2,4)/((15,5 + 4,5) : 2 1/2) · 5 3/7 − (2 1/2 + 1 1/3) : 1/6; ё) (2 7/15 + 1 7/12) · 1 1/9 − 1 7/8; ж) (6 1/7 − 5 3/4) : 1 11/14 + (3 3/4 − 1 5/6) : 1/6.

а) \(-15.64 : 4\frac{3}{5}+7.1\)\(\cdot\)2\(\frac{2}{5}\)=\(-\frac{391}{25}\cdot\frac{5}{23}+\frac{71}{10}\)\(\cdot\)\(\frac{12}{5}\)=\(-\frac{17}{5}+\frac{71}{10}\)\(\cdot\)\(\frac{12}{5}\)=\(\frac{37}{10}\)\(\cdot\)\(\frac{12}{5}\)=\(\frac{222}{25}\)=8.88.

б) \(0.4-\frac{11}{15}\)\(\cdot\)1\(\frac{2}{7}\)-\(\frac{7}{18}-0.5\):1\(\frac{1}{6}\)=\(-\frac15\)\(\cdot\)\(\frac\)97-\(-\frac19\):\(\frac\)76=-\(\frac\)9{35}+\(\frac\)2{21}=-\(\frac{13}{105}\).

в) 0.8:\(\frac{37.12-5.6\cdot0.14}{1.21+3.4+0.35}\)=\(\frac\)45:\(\frac{36.336}{4.96}\)=\(\frac\)45:\(\frac{453}{62}\)=\(\frac{248}{453}\).

г) \(2.17\cdot3.7-1.83\cdot2.3\):19.1=(8.029-4.209):19.1=3.82:19.1=0.2.

д) 5\(\frac\)4{19}\(\cdot\)3\(\frac\)47-1\(\frac{15}{19}\):\(\frac\)7{25}-1\(\frac\)23=\(\frac{99}{19}\)\(\cdot\)\(\frac{25}{7}\)-\(\frac{34}{19}\)\(\cdot\)\(\frac{25}{7}\)-\(\frac\)53=\(\frac{65}{7}\)-\(\frac\)53=\(\frac{160}{21}\)=7\(\frac{13}{21}\).

е) \(\frac\){\(3\frac13-2\frac23\)\(\cdot\)2.4}{(15.5+4.5):2\(\frac\)12}\(\cdot\)5\(\frac\)37-\(2\frac12+1\frac13\):\(\frac\)16=\(\frac{\frac83}{8}\)\(\cdot\)\(\frac{38}{7}\)-\(\frac{23}{6}\)\(\cdot\)6=\(\frac{76}{21}\)-23=-\(\frac{407}{21}\).

ё) \(2\frac7{15}+1\frac7{12}\)\(\cdot\)1\(\frac\)19-1\(\frac\)78=\(\left\)\(\frac{37}{15}+\frac{19}{12}\right\)\(\cdot\)\(\frac{10}{9}\)-\(\frac{15}{8}\)=\(\frac{761}{162}\)-\(\frac{15}{8}\)=\(\frac{293}{648}\).

ж) \(6\frac17-5\frac34\):1\(\frac{11}{14}\)+\(3\frac34-1\frac56\):\(\frac\)16=\(\left\)\(\frac{13}{28}:\frac{25}{14}\right\)+\(\frac{23}{12}\)\(\cdot\)6=\(\frac{13}{50}\)+\(\frac{23}{2}\)=\(\frac{294}{25}\)=11\(\frac{19}{25}\).