Вычислите значения выражений в столбце B: 1) 4√0,01 + √0,09; 2) 1/3√0,81 + √0,49; 3) 0,25√0,25 − √16; 4) 2³ + 5√36; 5) √(2² + 3 · 7); 6) 3√121 − 2√144; 7) √(3² + 4²); 8) 2√(3 · 27) − 6√(2 · 18); 9) √(10² − 4 · 3²); 10) √(4³ + 2³ · 10); 11) √(5² + 2³ · 7); 12) √64 · √100 · √0,16; 13) 2√0,81 + √0,04; 14) 3√25 − 1/3√81; 15) 1/4√(16/25) + 7√0,09; 16) 6√(1 13/36) − 7√(2 2/49); 17) 1/5√(1 9/16) − 2/3√(1 17/64); 18) √(16/25) · √(225/64).

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Accepted Answer

\(4\sqrt{0{,}01}+\sqrt{0{,}09}=4\cdot0{,}1+0{,}3=0{,}7\).
\(\frac13\sqrt{0{,}81}+\sqrt{0{,}49}=\frac13\cdot0{,}9+0{,}7=1\).
\(0{,}25\sqrt{0{,}25}-\sqrt{16}=0{,}25\cdot0{,}5-4=-3{,}875\).
\(2^3+5\sqrt{36}=8+5\cdot6=38\).
\(\sqrt{2^2+3\cdot7}=\sqrt{25}=5\).
\(3\sqrt{121}-2\sqrt{144}=3\cdot11-2\cdot12=9\).
\(\sqrt{3^2+4^2}=\sqrt{25}=5\).
\(2\sqrt{3\cdot27}-6\sqrt{2\cdot18}=2\cdot9-6\cdot6=-18\).
\(\sqrt{10^2-4\cdot3^2}=\sqrt{64}=8\).
\(\sqrt{4^3+2^3\cdot10}=\sqrt{144}=12\).
\(\sqrt{5^2+2^3\cdot7}=\sqrt{81}=9\).
\(\sqrt{64}\cdot\sqrt{100}\cdot\sqrt{0{,}16}=8\cdot10\cdot0{,}4=32\).
\(2\sqrt{0{,}81}+\sqrt{0{,}04}=2\cdot0{,}9+0{,}2=2\).
\(3\sqrt{25}-\frac13\sqrt{81}=3\cdot5-\frac13\cdot9=12\).
\(\frac14\sqrt{\frac{16}{25}}+7\sqrt{0{,}09}=\frac14\cdot\frac45+7\cdot0{,}3=2{,}3\).
\(6\sqrt{1\frac{13}{36}}-7\sqrt{2\frac2{49}}=6\cdot\frac76-7\cdot\frac{10}{7}=7-10=-3\).
\(\frac15\sqrt{1\frac9{16}}-\frac23\sqrt{1\frac{17}{64}}=\frac15\cdot\frac54-\frac23\cdot\frac98=\frac14-\frac34=-\frac12\).
\(\sqrt{\frac{16}{25}}\cdot\sqrt{\frac{225}{64}}=\frac45\cdot\frac{15}{8}=\frac32\).

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