Решим примеры:
- \(2\frac{1}{2}\cdot 1\frac{1}{5}-2\frac{2}{15}:2=\frac{5}{2}\cdot \frac{6}{5}-\frac{32}{15}:2=\frac{5\cdot 6}{2\cdot 5}-\frac{32}{15}\cdot \frac{1}{2}=\frac{6}{2}-\frac{16}{15}=3-\frac{16}{15}=\frac{45}{15}-\frac{16}{15}=\frac{29}{15}=1\frac{14}{15}\)
- \(4\frac{3}{7}\cdot 8\frac{4}{9}-4\frac{3}{7}\cdot 6\frac{4}{9}=\frac{31}{7}\cdot \frac{76}{9}-\frac{31}{7}\cdot \frac{58}{9}=\frac{31}{7}\cdot (\frac{76}{9}-\frac{58}{9})=\frac{31}{7}\cdot \frac{18}{9}=\frac{31}{7}\cdot 2=\frac{62}{7}=8\frac{6}{7}\)
Ответ: a) \(1\frac{14}{15}\), б) \(8\frac{6}{7}\)