98. Вычислите.
а) \(\frac{1}{2} : \frac{4}{7} = \frac{1}{2} \cdot \frac{7}{4} = \frac{7}{8}\)
б) \(\frac{3}{7} : \frac{3}{9} = \frac{3}{7} \cdot \frac{9}{3} = \frac{9}{7} = 1\frac{2}{7}\)
в) \(\frac{4}{9} : \frac{1}{2} = \frac{4}{9} \cdot \frac{2}{1} = \frac{8}{9}\)
г) \(\frac{3}{2} : \frac{3}{2} = \frac{3}{2} \cdot \frac{2}{3} = 1\)
д) \(\frac{4}{7} : \frac{4}{3} = \frac{4}{7} \cdot \frac{3}{4} = \frac{3}{7}\)
е) \(\frac{9}{11} : \frac{1}{3} = \frac{9}{11} \cdot \frac{3}{1} = \frac{27}{11} = 2\frac{5}{11}\)
ж) \(\frac{7}{9} : \frac{2}{3} = \frac{7}{9} \cdot \frac{3}{2} = \frac{7}{3 \cdot 3} \cdot \frac{3}{2} = \frac{7}{6} = 1\frac{1}{6}\)
з) \(\frac{3}{9} : \frac{1}{3} = \frac{3}{9} \cdot \frac{3}{1} = \frac{1}{3} \cdot \frac{3}{1} = 1\)
и) \(\frac{1}{5} : \frac{3}{25} = \frac{1}{5} \cdot \frac{25}{3} = \frac{25}{15} = \frac{5}{3} = 1\frac{2}{3}\)
к) \(\frac{7}{35} : \frac{3}{5} = \frac{7}{35} \cdot \frac{5}{3} = \frac{1}{7} \cdot \frac{5}{3} = \frac{5}{21}\)
л) \(\frac{2}{9} : \frac{10}{27} = \frac{2}{9} \cdot \frac{27}{10} = \frac{1}{1} \cdot \frac{3}{5} = \frac{3}{5}\)
м) \(\frac{6}{49} : \frac{3}{7} = \frac{6}{49} \cdot \frac{7}{3} = \frac{6}{7 \cdot 7} \cdot \frac{7}{3} = \frac{2}{7}\)
99. Вычислите.
а) \(\frac{3}{4} : \frac{3}{4} = \frac{3}{4} \cdot \frac{4}{3} = 1\)
б) \(0 : \frac{7}{8} = 0\)
в) \(1 : \frac{5}{9} = 1 \cdot \frac{9}{5} = \frac{9}{5} = 1\frac{4}{5}\)
г) \(\frac{3}{4} : \frac{2}{13} = \frac{3}{4} \cdot \frac{13}{2} = \frac{39}{8} = 4\frac{7}{8}\)
д) \(1 : \frac{1}{9} = 1 \cdot \frac{9}{1} = 9\)
е) \(\frac{6}{22} : \frac{6}{22} = 1\)
ж) \(0 : \frac{24}{33} = 0\)
з) \(1 : \frac{7}{25} = 1 \cdot \frac{25}{7} = \frac{25}{7} = 3\frac{4}{7}\)
и) \(1 : \frac{9}{11} = 1 \cdot \frac{11}{9} = \frac{11}{9} = 1\frac{2}{9}\)
Ответ: См. решение