2. Вычислите: a) 1.3-4:4; 6) 3륵.1+3륵.1.

a) $$1 \frac{1}{2} \cdot 3 \frac{1}{3}-4 \frac{4}{9}:4 = \frac{3}{2} \cdot \frac{10}{3} - \frac{40}{9}:4 = \frac{30}{6} - \frac{40}{9} \cdot \frac{1}{4} = 5 - \frac{10}{9} = \frac{45}{9} - \frac{10}{9} = \frac{35}{9} = 3 \frac{8}{9}$$

б) $$3 \frac{2}{7} \cdot 1 \frac{1}{3}+3 \frac{2}{7} \cdot 1 \frac{2}{3} = 3 \frac{2}{7} \cdot (1 \frac{1}{3}+1 \frac{2}{3}) = 3 \frac{2}{7} \cdot (\frac{4}{3}+\frac{5}{3}) = \frac{23}{7} \cdot \frac{9}{3} = \frac{23}{7} \cdot 3 = \frac{69}{7} = 9 \frac{6}{7}$$

Ответ: a) $$3 \frac{8}{9}$$, б) $$9 \frac{6}{7}$$