a) \( \frac{1}{2} + \frac{1}{3} \) = \( \frac{3}{6} + \frac{2}{6} \) = \( \frac{5}{6} \)
б) \( \frac{1}{3} + \frac{2}{7} \) = \( \frac{7}{21} + \frac{6}{21} \) = \( \frac{13}{21} \)
в) \( \frac{2}{5} + \frac{1}{3} \) = \( \frac{6}{15} + \frac{5}{15} \) = \( \frac{11}{15} \)
г) \( \frac{3}{7} + \frac{4}{9} \) = \( \frac{27}{63} + \frac{28}{63} \) = \( \frac{55}{63} \)
д) \( \frac{5}{9} - \frac{1}{6} \) = \( \frac{10}{18} - \frac{3}{18} \) = \( \frac{7}{18} \)
е) \( 3\frac{3}{4} - 4\frac{1}{3} \) = \( \frac{15}{4} - \frac{13}{3} \) = \( \frac{45}{12} - \frac{52}{12} \) = \( -\frac{7}{12} \)
ж) \( \frac{1}{6} + \frac{1}{3} \) = \( \frac{1}{6} + \frac{2}{6} \) = \( \frac{3}{6} \) = \( \frac{1}{2} \)
з) \( \frac{9}{5} - \frac{7}{10} \) = \( \frac{18}{10} - \frac{7}{10} \) = \( \frac{11}{10} \) = \( 1\frac{1}{10} \)
и) \( 4\frac{1}{2} - 1\frac{3}{8} \) = \( \frac{9}{2} - \frac{11}{8} \) = \( \frac{36}{8} - \frac{11}{8} \) = \( \frac{25}{8} \) = \( 3\frac{1}{8} \)
к) \( \frac{7}{15} - \frac{3}{10} \) = \( \frac{14}{30} - \frac{9}{30} \) = \( \frac{5}{30} \) = \( \frac{1}{6} \)
л) \( \frac{3}{8} + \frac{5}{12} \) = \( \frac{9}{24} + \frac{10}{24} \) = \( \frac{19}{24} \)
м) Тут ошибка в условии: должно быть 2 5/9 - 1 1/6 = \(\frac{23}{9} - \frac{7}{6} \) = \( \frac{46}{18} - \frac{21}{18} \) = \( \frac{25}{18} \) = \( 1 \frac{7}{18} \)
н) \( \frac{5}{11} + \frac{3}{5} \) = \( \frac{25}{55} + \frac{33}{55} \) = \( \frac{58}{55} \) = \( 1\frac{3}{55} \)
о) \( \frac{17}{30} - \frac{3}{6} \) = \( \frac{17}{30} - \frac{15}{30} \) = \( \frac{2}{30} \) = \( \frac{1}{15} \)
п) \( 3\frac{17}{35} - \frac{71}{4} \) = \(\frac{122}{35} - \frac{29}{4} \) = \( \frac{488}{140} - \frac{1015}{140} \) = \( -\frac{527}{140} \) = \( -3\frac{107}{140} \)