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МатематикаВопрос:
Выдели целую часть из неправильной дроби (перенеси единицу): 1) 3 20/17 = 2) 2 5/3 = 3) 14 17/15 = 4) 1 18/13 = 5) 7 9/7 = 6) 5 13/10 = 7) 2 19/11 = 8) 4 11/6 = 9) 6 17/9 = 10) 3 14/11 = 11) 8 7/5 = 12) 13 5/4 = 13) 1 19/12 = 14) 2 27/14 = 15) 6 15/8 = 16) 5 29/16 = 17) 4 39/27 = 18) 8 100/53 =
Ответ:
- 3 \frac{20}{17} = 3 + \frac{20}{17} = 3 + 1 \frac{3}{17} = 4 \frac{3}{17}
- 2 \frac{5}{3} = 2 + \frac{5}{3} = 2 + 1 \frac{2}{3} = 3 \frac{2}{3}
- 14 \frac{17}{15} = 14 + \frac{17}{15} = 14 + 1 \frac{2}{15} = 15 \frac{2}{15}
- 1 \frac{18}{13} = 1 + \frac{18}{13} = 1 + 1 \frac{5}{13} = 2 \frac{5}{13}
- 7 \frac{9}{7} = 7 + \frac{9}{7} = 7 + 1 \frac{2}{7} = 8 \frac{2}{7}
- 5 \frac{13}{10} = 5 + \frac{13}{10} = 5 + 1 \frac{3}{10} = 6 \frac{3}{10}
- 2 \frac{19}{11} = 2 + \frac{19}{11} = 2 + 1 \frac{8}{11} = 3 \frac{8}{11}
- 4 \frac{11}{6} = 4 + \frac{11}{6} = 4 + 1 \frac{5}{6} = 5 \frac{5}{6}
- 6 \frac{17}{9} = 6 + \frac{17}{9} = 6 + 1 \frac{8}{9} = 7 \frac{8}{9}
- 3 \frac{14}{11} = 3 + \frac{14}{11} = 3 + 1 \frac{3}{11} = 4 \frac{3}{11}
- 8 \frac{7}{5} = 8 + \frac{7}{5} = 8 + 1 \frac{2}{5} = 9 \frac{2}{5}
- 13 \frac{5}{4} = 13 + \frac{5}{4} = 13 + 1 \frac{1}{4} = 14 \frac{1}{4}
- 1 \frac{19}{12} = 1 + \frac{19}{12} = 1 + 1 \frac{7}{12} = 2 \frac{7}{12}
- 2 \frac{27}{14} = 2 + \frac{27}{14} = 2 + 1 \frac{13}{14} = 3 \frac{13}{14}
- 6 \frac{15}{8} = 6 + \frac{15}{8} = 6 + 1 \frac{7}{8} = 7 \frac{7}{8}
- 5 \frac{29}{16} = 5 + \frac{29}{16} = 5 + 1 \frac{13}{16} = 6 \frac{13}{16}
- 4 \frac{39}{27} = 4 + \frac{39}{27} = 4 + 1 \frac{12}{27} = 5 \frac{12}{27} = 5 \frac{4}{9}
- 8 \frac{100}{53} = 8 + \frac{100}{53} = 8 + 1 \frac{47}{53} = 9 \frac{47}{53}
