Выдели целую часть из неправильной дроби (перенеси единицу): 1) 3 20/17 = 2) 2 5/3 = 3) 14 17/15 = 4) 1 18/13 = 5) 7 9/7 = 6) 5 13/10 = 7) 2 19/11 = 8) 4 11/6 = 9) 6 17/9 = 10) 3 14/11 = 11) 8 7/5 = 12) 13 5/4 = 13) 1 19/12 = 14) 2 27/14 = 15) 6 15/8 = 16) 5 29/16 = 17) 4 39/27 = 18) 8 100/53 =

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ФИО:Телефон:Емаил:Полное описание сути нарушения прав (почему распространение данной информации запрещено Правообладателем):

Accepted Answer

3 \(\frac{20}{17}\) = 3 + \(\frac{20}{17}\) = 3 + 1 \(\frac{3}{17}\) = 4 \(\frac{3}{17}\)

2 \(\frac{5}{3}\) = 2 + \(\frac{5}{3}\) = 2 + 1 \(\frac{2}{3}\) = 3 \(\frac{2}{3}\)

14 \(\frac{17}{15}\) = 14 + \(\frac{17}{15}\) = 14 + 1 \(\frac{2}{15}\) = 15 \(\frac{2}{15}\)

1 \(\frac{18}{13}\) = 1 + \(\frac{18}{13}\) = 1 + 1 \(\frac{5}{13}\) = 2 \(\frac{5}{13}\)

7 \(\frac{9}{7}\) = 7 + \(\frac{9}{7}\) = 7 + 1 \(\frac{2}{7}\) = 8 \(\frac{2}{7}\)

5 \(\frac{13}{10}\) = 5 + \(\frac{13}{10}\) = 5 + 1 \(\frac{3}{10}\) = 6 \(\frac{3}{10}\)

2 \(\frac{19}{11}\) = 2 + \(\frac{19}{11}\) = 2 + 1 \(\frac{8}{11}\) = 3 \(\frac{8}{11}\)

4 \(\frac{11}{6}\) = 4 + \(\frac{11}{6}\) = 4 + 1 \(\frac{5}{6}\) = 5 \(\frac{5}{6}\)

6 \(\frac{17}{9}\) = 6 + \(\frac{17}{9}\) = 6 + 1 \(\frac{8}{9}\) = 7 \(\frac{8}{9}\)

3 \(\frac{14}{11}\) = 3 + \(\frac{14}{11}\) = 3 + 1 \(\frac{3}{11}\) = 4 \(\frac{3}{11}\)

8 \(\frac{7}{5}\) = 8 + \(\frac{7}{5}\) = 8 + 1 \(\frac{2}{5}\) = 9 \(\frac{2}{5}\)

13 \(\frac{5}{4}\) = 13 + \(\frac{5}{4}\) = 13 + 1 \(\frac{1}{4}\) = 14 \(\frac{1}{4}\)

1 \(\frac{19}{12}\) = 1 + \(\frac{19}{12}\) = 1 + 1 \(\frac{7}{12}\) = 2 \(\frac{7}{12}\)

2 \(\frac{27}{14}\) = 2 + \(\frac{27}{14}\) = 2 + 1 \(\frac{13}{14}\) = 3 \(\frac{13}{14}\)

6 \(\frac{15}{8}\) = 6 + \(\frac{15}{8}\) = 6 + 1 \(\frac{7}{8}\) = 7 \(\frac{7}{8}\)

5 \(\frac{29}{16}\) = 5 + \(\frac{29}{16}\) = 5 + 1 \(\frac{13}{16}\) = 6 \(\frac{13}{16}\)

4 \(\frac{39}{27}\) = 4 + \(\frac{39}{27}\) = 4 + 1 \(\frac{12}{27}\) = 5 \(\frac{12}{27}\) = 5 \(\frac{4}{9}\)

8 \(\frac{100}{53}\) = 8 + \(\frac{100}{53}\) = 8 + 1 \(\frac{47}{53}\) = 9 \(\frac{47}{53}\)