Ответ:
Выделяем единицу из неправильной дроби и прибавляем её к целой части:
- \(3\dfrac{20}{17}=3+1\dfrac{3}{17}=4\dfrac{3}{17}\);
- \(2\dfrac{5}{3}=2+1\dfrac{2}{3}=3\dfrac{2}{3}\);
- \(14\dfrac{17}{15}=14+1\dfrac{2}{15}=15\dfrac{2}{15}\);
- \(1\dfrac{18}{13}=1+1\dfrac{5}{13}=2\dfrac{5}{13}\);
- \(7\dfrac{9}{7}=7+1\dfrac{2}{7}=8\dfrac{2}{7}\);
- \(5\dfrac{13}{10}=5+1\dfrac{3}{10}=6\dfrac{3}{10}\);
- \(2\dfrac{19}{11}=2+1\dfrac{8}{11}=3\dfrac{8}{11}\);
- \(4\dfrac{11}{6}=4+1\dfrac{5}{6}=5\dfrac{5}{6}\);
- \(6\dfrac{17}{9}=6+1\dfrac{8}{9}=7\dfrac{8}{9}\);
- \(3\dfrac{14}{11}=3+1\dfrac{3}{11}=4\dfrac{3}{11}\);
- \(8\dfrac{7}{5}=8+1\dfrac{2}{5}=9\dfrac{2}{5}\);
- \(13\dfrac{5}{4}=13+1\dfrac{1}{4}=14\dfrac{1}{4}\);
- \(1\dfrac{19}{12}=1+1\dfrac{7}{12}=2\dfrac{7}{12}\);
- \(2\dfrac{27}{14}=2+1\dfrac{13}{14}=3\dfrac{13}{14}\);
- \(6\dfrac{15}{8}=6+1\dfrac{7}{8}=7\dfrac{7}{8}\);
- \(5\dfrac{29}{16}=5+1\dfrac{13}{16}=6\dfrac{13}{16}\);
- \(4\dfrac{39}{27}=4+1\dfrac{12}{27}=5\dfrac{12}{27}=5\dfrac{4}{9}\);
- \(8\dfrac{100}{53}=8+1\dfrac{47}{53}=9\dfrac{47}{53}\).
