Решение примеров:

1. $$10\frac{5}{14}-8\frac{3}{14} = (10 - 8) + (\frac{5}{14} - \frac{3}{14}) = 2 + \frac{2}{14} = 2 + \frac{1}{7} = 2\frac{1}{7}$$
2. $$7\frac{5}{6}-1 = (7-1) + \frac{5}{6} = 6 + \frac{5}{6} = 6\frac{5}{6}$$
3. $$1\frac{3}{16} = 1 + \frac{3}{16} = \frac{16}{16} + \frac{3}{16} = \frac{19}{16} = 1\frac{3}{16}$$
4. $$14\frac{1}{21}-4\frac{19}{21} = 14\frac{1}{21}-4\frac{19}{21} = 13\frac{22}{21} - 4\frac{19}{21} = (13-4) + (\frac{22}{21} - \frac{19}{21}) = 9 + \frac{3}{21} = 9 + \frac{1}{7} = 9\frac{1}{7}$$
5. $$11\frac{13}{40}-10\frac{23}{40} = 11\frac{13}{40}-10\frac{23}{40} = 10\frac{53}{40} - 10\frac{23}{40} = (10-10) + (\frac{53}{40} - \frac{23}{40}) = 0 + \frac{30}{40} = \frac{3}{4}$$
6. $$12\frac{7}{11}-10\frac{10}{11} = 12\frac{7}{11}-10\frac{10}{11} = 11\frac{18}{11} - 10\frac{10}{11} = (11-10) + (\frac{18}{11} - \frac{10}{11}) = 1 + \frac{8}{11} = 1\frac{8}{11}$$
7. $$\frac{17}{26}-\frac{15}{26} = \frac{17-15}{26} = \frac{2}{26} = \frac{1}{13}$$
8. $$9\frac{1}{33}-\frac{4}{33} = 9\frac{1}{33}-\frac{4}{33} = 8\frac{34}{33} - \frac{4}{33} = 8 + \frac{34-4}{33} = 8 + \frac{30}{33} = 8\frac{10}{11}$$
9. $$27\frac{7}{9}-11\frac{7}{9} = (27 - 11) + (\frac{7}{9} - \frac{7}{9}) = 16 + 0 = 16$$
10. $$2\frac{7}{42}-1\frac{13}{42} = 2\frac{7}{42}-1\frac{13}{42} = 1\frac{49}{42} - 1\frac{13}{42} = (1-1) + (\frac{49}{42} - \frac{13}{42}) = 0 + \frac{36}{42} = \frac{6}{7}$$
11. $$8-3\frac{1}{12} = 7\frac{12}{12} - 3\frac{1}{12} = (7-3) + (\frac{12}{12} - \frac{1}{12}) = 4 + \frac{11}{12} = 4\frac{11}{12}$$
12. $$1\frac{2}{25}-\frac{11}{25} = 1\frac{2}{25}-\frac{11}{25} = \frac{27}{25} - \frac{11}{25} = \frac{27-11}{25} = \frac{16}{25}$$