Выполним действия с дробями:
- \(\frac{5}{7} - \frac{2}{7} + \frac{6}{7} = \frac{5-2+6}{7} = \frac{9}{7}\)
- \(\frac{3}{4} + \frac{1}{4} + \frac{2}{4} = \frac{3+1+2}{4} = \frac{6}{4} = \frac{3}{2}\)
- \(\frac{14}{10} - \frac{5}{10} - \frac{8}{10} = \frac{14-5-8}{10} = \frac{1}{10}\)
- \(\frac{19}{21} + \frac{7}{21} - \frac{5}{21} = \frac{19+7-5}{21} = \frac{21}{21} = 1\)
Ответ:
- $$\frac{9}{7}$$
- $$\frac{3}{2}$$
- $$\frac{1}{10}$$
- $$1$$