a) $$\frac{15}{7} \cdot \frac{28}{9} = \frac{15 \cdot 28}{7 \cdot 9} = \frac{15 \cdot 4}{1 \cdot 9} = \frac{60}{9} = 6 \frac{6}{9} = 6 \frac{2}{3}$$
б) $$\frac{28}{7} \cdot \frac{7}{9} = \frac{28 \cdot 7}{7 \cdot 9} = \frac{28}{9} = 3 \frac{1}{9}$$
в) $$\frac{5}{8} \cdot \frac{28}{15} \cdot \frac{16}{7} = \frac{5 \cdot 28 \cdot 16}{8 \cdot 15 \cdot 7} = \frac{1 \cdot 4 \cdot 2}{1 \cdot 3 \cdot 1} = \frac{8}{3} = 2 \frac{2}{3}$$
Ответ: a) $$6 \frac{2}{3}$$, б) $$3 \frac{1}{9}$$, в) $$2 \frac{2}{3}$$