Ответ:
Краткое пояснение: Чтобы разделить дроби, умножьте первую дробь на перевернутую вторую.
- 1) a) \(\frac{5}{9} : \frac{3}{4} = \frac{5}{9} \cdot \frac{4}{3} = \frac{5 \cdot 4}{9 \cdot 3} = \frac{20}{27}\)
- 6) \(\frac{1}{6} : \frac{1}{2} = \frac{1}{6} \cdot \frac{2}{1} = \frac{1 \cdot 2}{6 \cdot 1} = \frac{2}{6} = \frac{1}{3}\)
- B) \(\frac{7}{12} : \frac{1}{5} = \frac{7}{12} \cdot \frac{5}{1} = \frac{7 \cdot 5}{12 \cdot 1} = \frac{35}{12} = 2 \frac{11}{12}\)
- г) \(\frac{3}{11} : \frac{3}{6} = \frac{3}{11} \cdot \frac{6}{3} = \frac{3 \cdot 6}{11 \cdot 3} = \frac{18}{33} = \frac{6}{11}\)
- 2) a) \(\frac{1}{9} : \frac{1}{3} = \frac{1}{9} \cdot \frac{3}{1} = \frac{1 \cdot 3}{9 \cdot 1} = \frac{3}{9} = \frac{1}{3}\)
- 6) \(\frac{4}{7} : \frac{4}{12} = \frac{4}{7} \cdot \frac{12}{4} = \frac{4 \cdot 12}{7 \cdot 4} = \frac{48}{28} = \frac{12}{7} = 1 \frac{5}{7}\)
- B) \(\frac{9}{16} : \frac{3}{4} = \frac{9}{16} \cdot \frac{4}{3} = \frac{9 \cdot 4}{16 \cdot 3} = \frac{36}{48} = \frac{3}{4}\)
- г) \(\frac{10}{21} : \frac{1}{15} = \frac{10}{21} \cdot \frac{15}{1} = \frac{10 \cdot 15}{21 \cdot 1} = \frac{150}{21} = \frac{50}{7} = 7 \frac{1}{7}\)
- 3) a) \(\frac{1}{8} : \frac{1}{4} = \frac{1}{8} \cdot \frac{4}{1} = \frac{1 \cdot 4}{8 \cdot 1} = \frac{4}{8} = \frac{1}{2}\)
- 6) \(\frac{1}{5} : \frac{1}{25} = \frac{1}{5} \cdot \frac{25}{1} = \frac{1 \cdot 25}{5 \cdot 1} = \frac{25}{5} = 5\)
- B) \(\frac{3}{10} : \frac{1}{100} = \frac{3}{10} \cdot \frac{100}{1} = \frac{3 \cdot 100}{10 \cdot 1} = \frac{300}{10} = 30\)
- г) \(\frac{1}{15} : \frac{1}{15} = \frac{1}{15} \cdot \frac{15}{1} = \frac{1 \cdot 15}{15 \cdot 1} = \frac{15}{15} = 1\)
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