\( 1.7\frac{5}{16}+8\frac{11}{16} = (1+8)+(\frac{5}{16}+\frac{11}{16}) = 9 + \frac{16}{16} = 9 + 1 = 10 \)
\( 2.5\frac{10}{23}+8\frac{18}{23} = (5+8)+(\frac{10}{23}+\frac{18}{23}) = 13 + \frac{28}{23} = 13 + 1\frac{5}{23} = 14\frac{5}{23} \)
\( 3. 14\frac{6}{10}-\frac{5}{20} = 14\frac{12}{20}-\frac{5}{20} = 14\frac{7}{20} \)
\( 4. 6\frac{1}{7}-2\frac{2}{3} = 6\frac{3}{21}-2\frac{14}{21} = 5\frac{24}{21}-2\frac{14}{21} = 3\frac{10}{21} \)
\( \frac{183}{6} = 30\frac{3}{6} = 30\frac{1}{2} \)
\( \frac{93}{34} = 2\frac{25}{34} \)
\( \frac{131}{15} = 8\frac{11}{15} \)
\( \frac{133}{9} = 14\frac{7}{9} \)
\( 14\frac{3}{4} = \frac{14 \cdot 4 + 3}{4} = \frac{56 + 3}{4} = \frac{59}{4} \)
\( 16\frac{5}{16} = \frac{16 \cdot 16 + 5}{16} = \frac{256 + 5}{16} = \frac{261}{16} \)
\( (5\frac{7}{44}-x)+4\frac{23}{47}=6\frac{1}{47} \)
\( 5\frac{7}{44}-x=6\frac{1}{47}-4\frac{23}{47} \)
\( 5\frac{7}{44}-x=1\frac{25}{47} \)
\( x=5\frac{7}{44}-1\frac{25}{47} \)
\( x=4\frac{7}{44}-\frac{25}{47} \)
\( x=4\frac{7\cdot 47 - 25 \cdot 44}{44 \cdot 47} \)
\( x=4\frac{329 - 1100}{2068} \)
\( x=4-\frac{771}{2068} \)
\( x=3\frac{2068-771}{2068} \)
\( x=3\frac{1297}{2068} \)
Ответ: 1) 10; 2) \(14\frac{5}{23}\); 3) \(14\frac{7}{20}\); 4) \(3\frac{10}{21}\); 1) \(30\frac{1}{2}\); 2) \(2\frac{25}{34}\); 3) \(8\frac{11}{15}\); 4) \(14\frac{7}{9}\); 1) \(\frac{59}{4}\); 2) \(\frac{261}{16}\); x=\(3\frac{1297}{2068}\)