Выполним действия и сократим дробную часть полученного результата:
- a) $$14 \frac{5}{18} - \frac{14}{18} = \frac{14 \cdot 18 + 5}{18} - \frac{14}{18} = \frac{252 + 5}{18} - \frac{14}{18} = \frac{257}{18} - \frac{14}{18} = \frac{257-14}{18} = \frac{243}{18} = \frac{243:9}{18:9} = \frac{27}{2} = 13 \frac{1}{2}$$
- б) $$ \frac{5}{22} + \frac{6}{22} = \frac{5+6}{22} = \frac{11}{22} = \frac{11:11}{22:11} = \frac{1}{2}$$
- в) $$6 \frac{7}{12} - 1 \frac{3}{12} = (6-1) + (\frac{7}{12} - \frac{3}{12}) = 5 + \frac{7-3}{12} = 5 + \frac{4}{12} = 5 + \frac{4:4}{12:4} = 5 + \frac{1}{3} = 5 \frac{1}{3}$$
- г) $$7 \frac{5}{27} + 3 \frac{4}{27} = (7+3) + (\frac{5}{27} + \frac{4}{27}) = 10 + \frac{5+4}{27} = 10 + \frac{9}{27} = 10 + \frac{9:9}{27:9} = 10 + \frac{1}{3} = 10 \frac{1}{3}$$
Ответ: a) $$13 \frac{1}{2}$$, б) $$\frac{1}{2}$$, в) $$5 \frac{1}{3}$$, г) $$10 \frac{1}{3}$$