a) $$\frac{14}{18} - \frac{5}{18} = \frac{14-5}{18} = \frac{9}{18} = \frac{1}{2}$$
б) $$\frac{5}{22} + \frac{6}{22} = \frac{5+6}{22} = \frac{11}{22} = \frac{1}{2}$$
в) $$6\frac{7}{12} - 1\frac{3}{12} = (6-1) + (\frac{7}{12} - \frac{3}{12}) = 5 + \frac{7-3}{12} = 5 + \frac{4}{12} = 5 + \frac{1}{3} = 5\frac{1}{3}$$
г) $$7\frac{5}{27} + 3\frac{4}{27} = (7+3) + (\frac{5}{27} + \frac{4}{27}) = 10 + \frac{5+4}{27} = 10 + \frac{9}{27} = 10 + \frac{1}{3} = 10\frac{1}{3}$$
Ответ: а) $$\frac{1}{2}$$, б) $$\frac{1}{2}$$, в) $$5\frac{1}{3}$$, г) $$10\frac{1}{3}$$