Выполните действие: a) (2a-1) / (3a) + (a+2) / (6a); б) 1/(x-3) - 1/(x+3)

Задание 2

1. a) $$ \frac{2a - 1}{3a} + \frac{a + 2}{6a} = \frac{2(2a - 1) + (a + 2)}{6a} = \frac{4a - 2 + a + 2}{6a} = \frac{5a}{6a} = \frac{5}{6} $$
2. б) $$ \frac{1}{x - 3} - \frac{1}{x + 3} = \frac{(x + 3) - (x - 3)}{(x - 3)(x + 3)} = \frac{x + 3 - x + 3}{x^2 - 9} = \frac{6}{x^2 - 9} $$