Решение:

1. $$6+\frac{7}{16} = \frac{6*16}{16} + \frac{7}{16} = \frac{96}{16} + \frac{7}{16} = \frac{96+7}{16} = \frac{103}{16} = 6\frac{7}{16}$$
2. $$4\frac{5}{23}+2\frac{12}{23} = (4+2) + (\frac{5}{23} + \frac{12}{23}) = 6 + \frac{5+12}{23} = 6 + \frac{17}{23} = 6\frac{17}{23}$$
3. $$2 - \frac{7}{8} = \frac{2*8}{8} - \frac{7}{8} = \frac{16}{8} - \frac{7}{8} = \frac{16-7}{8} = \frac{9}{8} = 1\frac{1}{8}$$
4. $$10\frac{13}{17}-6\frac{9}{17} = (10-6) + (\frac{13}{17} - \frac{9}{17}) = 4 + \frac{13-9}{17} = 4 + \frac{4}{17} = 4\frac{4}{17}$$

1. $$6\frac{7}{16}$$
2. $$6\frac{17}{23}$$
3. $$1\frac{1}{8}$$
4. $$4\frac{4}{17}$$