2.253 Выполните действия: a) $$4\frac{13}{24}+\frac{1}{8}-3\frac{1}{24}$$; б) $$3\frac{8}{9}+1\frac{3}{4}+\frac{1}{9}$$; в) $$5\frac{1}{2}-2\frac{7}{12}-2\frac{3}{10}$$; г) $$4\frac{2}{3}+2\frac{3}{4}-1\frac{5}{12}$$.

a) $$4\frac{13}{24}+\frac{1}{8}-3\frac{1}{24} = 4\frac{13}{24}+\frac{3}{24}-3\frac{1}{24} = 1\frac{12+3}{24} = 1\frac{15}{24} = 1\frac{5}{8}$$

б) $$3\frac{8}{9}+1\frac{3}{4}+\frac{1}{9} = 3\frac{8}{9}+1\frac{1}{9}+1\frac{3}{4} = 4\frac{9}{9} + 1\frac{3}{4} = 5 + \frac{3}{4} = 5\frac{3}{4}$$

в) $$5\frac{1}{2}-2\frac{7}{12}-2\frac{3}{10} = 5\frac{6}{12}-2\frac{7}{12}-2\frac{3}{10} = 4\frac{18}{12}-2\frac{7}{12}-2\frac{3}{10} = 2\frac{11}{12}-2\frac{3}{10} = 2\frac{55}{60}-2\frac{18}{60} = \frac{37}{60}$$

г) $$4\frac{2}{3}+2\frac{3}{4}-1\frac{5}{12} = 4\frac{8}{12}+2\frac{9}{12}-1\frac{5}{12} = 6\frac{17}{12}-1\frac{5}{12} = 5\frac{12}{12} = 6$$