32. Выполните действия над дробями, предварительно сократив их: 12 18 + 4 12 10 50 + 9 20 - 14 35 21 28 - 10 40 6 18 - 4 12 + 18 27 12 16 - 30 120 9 12 + 18 24 - 20 16

1. $$\frac{12}{18} + \frac{4}{12} = \frac{2}{3} + \frac{1}{3} = \frac{2+1}{3} = \frac{3}{3} = 1$$
2. $$\frac{10}{50} + \frac{9}{20} - \frac{14}{35} = \frac{1}{5} + \frac{9}{20} - \frac{2}{5} = \frac{4 + 9 - 8}{20} = \frac{5}{20} = \frac{1}{4}$$
3. $$\frac{21}{28} - \frac{10}{40} = \frac{3}{4} - \frac{1}{4} = \frac{3-1}{4} = \frac{2}{4} = \frac{1}{2}$$
4. $$\frac{6}{18} - \frac{4}{12} + \frac{18}{27} = \frac{1}{3} - \frac{1}{3} + \frac{2}{3} = \frac{1 - 1 + 2}{3} = \frac{2}{3}$$
5. $$\frac{12}{16} - \frac{30}{120} = \frac{3}{4} - \frac{1}{4} = \frac{3-1}{4} = \frac{2}{4} = \frac{1}{2}$$
6. $$\frac{9}{12} + \frac{18}{24} - \frac{20}{16} = \frac{3}{4} + \frac{3}{4} - \frac{5}{4} = \frac{3+3-5}{4} = \frac{1}{4}$$

Ответ: См. решение