Решение:
- а) \(\frac{16}{23} - \frac{12}{23} + \frac{3}{23} = \frac{16-12+3}{23} = \frac{7}{23}\)
- б) \(2\frac{5}{11} + 6\frac{7}{11} = (2+6) + (\frac{5}{11} + \frac{7}{11}) = 8 + \frac{12}{11} = 8 + 1\frac{1}{11} = 9\frac{1}{11}\)
- в) \(7 - 4\frac{4}{5} = 6\frac{5}{5} - 4\frac{4}{5} = (6-4) + (\frac{5}{5} - \frac{4}{5}) = 2\frac{1}{5}\)
- г) \(5\frac{4}{13} - 3\frac{9}{13} = 4\frac{17}{13} - 3\frac{9}{13} = (4-3) + (\frac{17}{13} - \frac{9}{13}) = 1 + \frac{8}{13} = 1\frac{8}{13}\)
Ответ: а) \(\frac{7}{23}\); б) \(9\frac{1}{11}\); в) \(2\frac{1}{5}\); г) \(1\frac{8}{13}\)