Вопрос:

1. Выполните действия: a) 2$$\frac{1}{7}$$\cdot$$4$$\frac{1}{6}$$-2$$\frac{1}{3}$$= б) 6$$\frac{3}{7}$$\cdot$$3$$\frac{1}{3}$$:1$$\frac{2}{7}$$= д) 5$$\frac{4}{19}$$\cdot$$3$$\frac{4}{7}$$+1$$\frac{15}{19}$$:$$\frac{7}{25}$$-$$\frac{2}{3}$$= e) 2$$\frac{3}{11}$$+6$$\frac{7}{9}$$:\frac{8}{11}$$\cdot$$1$$\frac{1}{7}$$-1$$\frac{1}{8}$$= в) (6$$\frac{1}{5}$$-4$$\frac{1}{3}$$):1$$\frac{1}{3}$$= г) (7$$\frac{2}{3}$$-5$$\frac{4}{5}$$):2$$\frac{4}{5}$$=

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Ответ:

a) 2$$\frac{1}{7}$$\cdot$$4$$\frac{1}{6}$$-2$$\frac{1}{3}$$=\frac{15}{7}$$\cdot$$\frac{25}{6}$$-$$\frac{7}{3}$$=\frac{15\cdot25}{7\cdot6}$$-$$\frac{7}{3}$$=\frac{375}{42}$$-$$\frac{7}{3}$$=\frac{375}{42}$$-$$\frac{7\cdot14}{3\cdot14}$$=\frac{375}{42}$$-$$\frac{98}{42}$$=\frac{375-98}{42}$$=\frac{277}{42}$$=6$$\frac{25}{42}$$

Ответ: 6$$\frac{25}{42}$$

б) 6$$\frac{3}{7}$$\cdot$$3$$\frac{1}{3}$$:1$$\frac{2}{7}$$=\frac{45}{7}$$\cdot$$\frac{10}{3}$$\div$$\frac{9}{7}$$=\frac{45}{7}$$\cdot$$\frac{10}{3}$$\cdot$$\frac{7}{9}$$=\frac{45\cdot10\cdot7}{7\cdot3\cdot9}$$=\frac{45\cdot10}{3\cdot9}$$=\frac{5\cdot10}{1\cdot1}$$=$$\frac{50}{3}$$=16$$\frac{2}{3}$$

Ответ: 16$$\frac{2}{3}$$

в) (6$$\frac{1}{5}$$-4$$\frac{1}{3}$$):1$$\frac{1}{3}$$=\frac{31}{5}$$-$$\frac{13}{3}$$\div$$\frac{4}{3}$$=(\frac{31\cdot3}{5\cdot3}$$-$$\frac{13\cdot5}{3\cdot5}$$)$$\div$$\frac{4}{3}$$=(\frac{93}{15}$$-$$\frac{65}{15}$$)$$\div$$\frac{4}{3}$$=\frac{93-65}{15}$$\cdot$$\frac{3}{4}$$=\frac{28}{15}$$\cdot$$\frac{3}{4}$$=\frac{28\cdot3}{15\cdot4}$$=\frac{7\cdot1}{5\cdot1}$$=\frac{7}{5}$$=1$$\frac{2}{5}$$

Ответ: 1$$\frac{2}{5}$$

г) (7$$\frac{2}{3}$$-5$$\frac{4}{5}$$):2$$\frac{4}{5}$$=(\frac{23}{3}$$-$$\frac{29}{5}$$)$$\div$$\frac{14}{5}$$=(\frac{23\cdot5}{3\cdot5}$$-$$\frac{29\cdot3}{5\cdot3}$$)$$\div$$\frac{14}{5}$$=(\frac{115}{15}$$-$$\frac{87}{15}$$)$$\div$$\frac{14}{5}$$=\frac{115-87}{15}$$\div$$\frac{14}{5}$$=\frac{28}{15}$$\div$$\frac{14}{5}$$=\frac{28}{15}$$\cdot$$\frac{5}{14}$$=\frac{28\cdot5}{15\cdot14}$$=\frac{2\cdot1}{3\cdot1}$$=\frac{2}{3}$$

Ответ: $$\frac{2}{3}$$

д) 5$$\frac{4}{19}$$\cdot$$3$$\frac{4}{7}$$+1$$\frac{15}{19}$$:$$\frac{7}{25}$$-$$\frac{2}{3}$$=\frac{99}{19}$$\cdot$$\frac{25}{7}$$+$$\frac{34}{19}$$\cdot$$\frac{25}{7}$$-$$\frac{2}{3}$$=\frac{99\cdot25}{19\cdot7}$$+$$\frac{34\cdot25}{19\cdot7}$$-$$\frac{2}{3}$$=\frac{2475}{133}$$+$$\frac{850}{133}$$-$$\frac{2}{3}$$=\frac{2475+850}{133}$$-$$\frac{2}{3}$$=\frac{3325}{133}$$-$$\frac{2}{3}$$=\frac{3325\cdot3}{133\cdot3}$$-$$\frac{2\cdot133}{3\cdot133}$$=\frac{9975}{399}$$-$$\frac{266}{399}$$=\frac{9975-266}{399}$$=\frac{9709}{399}$$=24$$\frac{13}{399}$$

Ответ: 24$$\frac{13}{399}$$

e) 2$$\frac{3}{11}$$+6$$\frac{7}{9}$$:\frac{8}{11}$$\cdot$$1$$\frac{1}{7}$$-1$$\frac{1}{8}$$=\frac{25}{11}$$+$$\frac{61}{9}$$\cdot$$\frac{11}{8}$$\cdot$$\frac{8}{7}$$-$$\frac{9}{8}$$=\frac{25}{11}$$+$$\frac{61\cdot11\cdot8}{9\cdot8\cdot7}$$-$$\frac{9}{8}$$=\frac{25}{11}$$+$$\frac{61\cdot11}{9\cdot7}$$-$$\frac{9}{8}$$=\frac{25}{11}$$+$$\frac{671}{63}$$-$$\frac{9}{8}$$=\frac{25\cdot504}{11\cdot504}$$+$$\frac{671\cdot88}{63\cdot88}$$-$$\frac{9\cdot693}{8\cdot693}$$=\frac{12600}{5544}$$+$$\frac{58048}{5544}$$-$$\frac{6237}{5544}$$=\frac{12600+58048-6237}{5544}$$=\frac{64411}{5544}$$=11$$\frac{3227}{5544}$$

Ответ: 11$$\frac{3227}{5544}$$

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