a) $$2\frac{1}{7}+3\frac{5}{7} = (2+3) + (\frac{1}{7} + \frac{5}{7}) = 5 + \frac{6}{7} = 5\frac{6}{7}$$
б) $$7\frac{4}{5}-5\frac{3}{5} = (7-5) + (\frac{4}{5} - \frac{3}{5}) = 2 + \frac{1}{5} = 2\frac{1}{5}$$
Ответ: a) $$5\frac{6}{7}$$, б) $$2\frac{1}{5}$$