Определим предмет: Математика.
2.395 Выполните действия:
a) $$\frac{27}{35} \cdot \frac{7}{9} - \frac{9}{24} \cdot \frac{6}{45} = \frac{3}{5} \cdot \frac{1}{1} - \frac{3}{8} \cdot \frac{1}{5} = \frac{3}{5} - \frac{3}{40} = \frac{24}{40} - \frac{3}{40} = \frac{21}{40}$$
б) $$1\frac{41}{44} \cdot \frac{11}{17} - \frac{27}{40} \cdot \frac{5}{18} = \frac{85}{44} \cdot \frac{11}{17} - \frac{3}{8} \cdot \frac{1}{2} = \frac{5}{4} \cdot \frac{1}{1} - \frac{3}{16} = \frac{5}{4} - \frac{3}{16} = \frac{20}{16} - \frac{3}{16} = \frac{17}{16} = 1\frac{1}{16}$$
в) $$12\frac{1}{10} \cdot 2\frac{4}{11} + 2\frac{24}{31} \cdot 7\frac{3}{4} = \frac{121}{10} \cdot \frac{26}{11} + \frac{86}{31} \cdot \frac{31}{4} = \frac{11}{5} \cdot \frac{13}{1} + \frac{43}{2} \cdot \frac{1}{1} = \frac{143}{5} + \frac{43}{2} = \frac{286}{10} + \frac{215}{10} = \frac{501}{10} = 50\frac{1}{10}$$
г) $$13\frac{2}{7} - 5\frac{5}{8} \cdot (1\frac{2}{9} - \frac{39}{45}) = \frac{93}{7} - \frac{45}{8} \cdot (\frac{11}{9} - \frac{13}{15}) = \frac{93}{7} - \frac{45}{8} \cdot (\frac{55}{45} - \frac{39}{45}) = \frac{93}{7} - \frac{45}{8} \cdot \frac{16}{45} = \frac{93}{7} - \frac{1}{1} \cdot \frac{2}{1} = \frac{93}{7} - 2 = \frac{93}{7} - \frac{14}{7} = \frac{79}{7} = 11\frac{2}{7}$$
д) $$(\frac{3}{5})^3 = \frac{3}{5} \cdot \frac{3}{5} \cdot \frac{3}{5} = \frac{27}{125}$$
e) $$(\frac{7}{8})^2 = \frac{7}{8} \cdot \frac{7}{8} = \frac{49}{64}$$
2.396 Вычислите:
1) $$(4,51 : 1,1 + 5,3) \cdot (8,4 - 10,23 : 3,1) = (4,1 + 5,3) \cdot (8,4 - 3,3) = 9,4 \cdot 5,1 = 47,94$$
2) $$(4,05 : 2,7 - 1,2) \cdot (2,5 + 8,37 : 2,7) = (1,5 - 1,2) \cdot (2,5 + 3,1) = 0,3 \cdot 5,6 = 1,68$$
2.397 Найдите произведение:
a) $$8\frac{4}{15} \cdot 2 = \frac{124}{15} \cdot 2 = \frac{248}{15} = 16\frac{8}{15}$$
б) $$3\frac{9}{14} \cdot 7 = \frac{51}{14} \cdot 7 = \frac{51}{2} = 25\frac{1}{2}$$
в) $$7\frac{4}{27} \cdot 5 = \frac{193}{27} \cdot 5 = \frac{965}{27} = 35\frac{20}{27}$$
г) $$8 \cdot 2\frac{1}{8} = 8 \cdot \frac{17}{8} = 17$$
д) $$5\frac{5}{6} \cdot 3 = \frac{35}{6} \cdot 3 = \frac{35}{2} = 17\frac{1}{2}$$
e) $$7\frac{7}{11} \cdot 11 = \frac{84}{11} \cdot 11 = 84$$