Решение:
a) $$\frac{10}{11} - \frac{4}{11} + \frac{3}{11} = \frac{10-4+3}{11} = \frac{9}{11}$$.
б) $$4\frac{5}{9} + 3\frac{8}{9} = (4+3) + (\frac{5}{9} + \frac{8}{9}) = 7 + \frac{13}{9} = 7 + 1\frac{4}{9} = 8\frac{4}{9}$$.
в) $$6 - 2\frac{3}{8} = 6 - \frac{2*8+3}{8} = 6 - \frac{19}{8} = \frac{6*8}{8} - \frac{19}{8} = \frac{48-19}{8} = \frac{29}{8} = 3\frac{5}{8}$$.
г) $$5\frac{6}{13} - 1\frac{11}{13} = \frac{5*13+6}{13} - \frac{1*13+11}{13} = \frac{71}{13} - \frac{24}{13} = \frac{71-24}{13} = \frac{47}{13} = 3\frac{8}{13}$$.
Ответы:
a) $$\frac{9}{11}$$; б) $$8\frac{4}{9}$$; в) $$3\frac{5}{8}$$; г) $$3\frac{8}{13}$$.