a) $$rac{12x^3}{25} cdot \frac{5}{4x^4} = \frac{12x^3 \cdot 5}{25 \cdot 4x^4} = \frac{3 \cdot 1}{5 \cdot x} = \frac{3}{5x}$$
б) $$(2x - 6) \cdot \frac{x^2}{x - 3} = \frac{2(x - 3) \cdot x^2}{x - 3} = 2x^2$$
в) $$\left(-\frac{3a}{b^2}\right)^2 = \frac{(-3a)^2}{(b^2)^2} = \frac{9a^2}{b^4}$$
г) $$\frac{y^2 - y}{2xy} \cdot \frac{2x}{y^2 - 1} = \frac{y(y - 1) \cdot 2x}{2xy \cdot (y - 1)(y + 1)} = \frac{1}{y + 1}$$
Ответ:
a) $$rac{3}{5x}$$
б) $$2x^2$$
в) $$rac{9a^2}{b^4}$$
г) $$rac{1}{y + 1}$$