4. Выполните сложение. а) 3$$\frac{3}{5}$$ + $$\frac{1}{5}$$ = 3+$$\frac{3}{5}$$ + $$\frac{1}{5}$$ = 3+(\frac{3}{5}$$ + $$\frac{1}{5}$$) = 3$$\frac{4}{5}$$ б) 4$$\frac{3}{7}$$ + 2$$\frac{4}{7}$$ = 6$$\frac{7}{7}$$ = 6+1=7 в) 3$$\frac{5}{6}$$ + $$\frac{1}{6}$$ = г) 15$$\frac{3}{8}$$ + $$\frac{4}{8}$$ = д) $$\frac{7}{11}$$ + 3$$\frac{2}{11}$$ = е) 9$$\frac{3}{10}$$ + 4$$\frac{1}{10}$$ = ж) 17$$\frac{5}{12}$$ +1$$\frac{7}{12}$$ = з) $$\frac{1}{9}$$ +9$$\frac{8}{9}$$ =

Выполним сложение смешанных чисел. а) 3$$\frac{3}{5}$$ + $$\frac{1}{5}$$ = 3+$$\frac{3}{5}$$ + $$\frac{1}{5}$$ = 3+(\frac{3}{5}$$ + $$\frac{1}{5}$$) = 3$$\frac{4}{5} \( 3\frac{3}{5} + \frac{1}{5} = 3 + \frac{3+1}{5} = 3\frac{4}{5} \) б) 4$$\frac{3}{7}$$ + 2$$\frac{4}{7}$$ = 6$$\frac{7}{7}$$ = 6+1=7 \( 4\frac{3}{7} + 2\frac{4}{7} = (4+2) + \frac{3+4}{7} = 6 + \frac{7}{7} = 6 + 1 = 7 \) в) 3$$\frac{5}{6}$$ + $$\frac{1}{6}$$ = 3$$\frac{6}{6}$$ = 4 \( 3\frac{5}{6} + \frac{1}{6} = 3 + \frac{5}{6} + \frac{1}{6} = 3 + \frac{5+1}{6} = 3 + \frac{6}{6} = 3 + 1 = 4 \) г) 15$$\frac{3}{8}$$ + $$\frac{4}{8}$$ = 15$$\frac{7}{8} \( 15\frac{3}{8} + \frac{4}{8} = 15 + \frac{3}{8} + \frac{4}{8} = 15 + \frac{3+4}{8} = 15 + \frac{7}{8} = 15\frac{7}{8} \) д) $$\frac{7}{11}$$ + 3$$\frac{2}{11}$$ = 3$$\frac{9}{11} \( \frac{7}{11} + 3\frac{2}{11} = 3 + \frac{7}{11} + \frac{2}{11} = 3 + \frac{7+2}{11} = 3 + \frac{9}{11} = 3\frac{9}{11} \) е) 9$$\frac{3}{10}$$ + 4$$\frac{1}{10}$$ = 13$$\frac{4}{10} \( 9\frac{3}{10} + 4\frac{1}{10} = (9+4) + \frac{3}{10} + \frac{1}{10} = 13 + \frac{3+1}{10} = 13 + \frac{4}{10} = 13\frac{4}{10} \) ж) 17$$\frac{5}{12}$$ +1$$\frac{7}{12}$$ = 18$$\frac{12}{12}$$ = 19 \( 17\frac{5}{12} + 1\frac{7}{12} = (17+1) + \frac{5}{12} + \frac{7}{12} = 18 + \frac{5+7}{12} = 18 + \frac{12}{12} = 18 + 1 = 19 \) з) $$\frac{1}{9}$$ +9$$\frac{8}{9}$$ = 9$$\frac{9}{9}$$ = 10 \( \frac{1}{9} + 9\frac{8}{9} = 9 + \frac{1}{9} + \frac{8}{9} = 9 + \frac{1+8}{9} = 9 + \frac{9}{9} = 9 + 1 = 10 \)

Ответ: смотри решение выше