Вопрос:

4.180 Выполните сложение: a) -1$$\frac{1}{2}$$ + (-2$$\frac{1}{2}$$); б) -4$$\frac{9}{14}$$ + (-1$$\frac{1}{7}$$); в) -5$$\frac{7}{12}$$ + (-2$$\frac{3}{4}$$); г) -3$$\frac{4}{9}$$ + (-8$$\frac{5}{6}$$); д) -5$$\frac{12}{17}$$ + (-$$\frac{15}{24}$$) + (-1$$\frac{3}{8}$$) + (-$$\frac{5}{17}$$); е) -$$\frac{9}{28}$$ + (-4$$\frac{9}{35}$$) + (-2$$\frac{5}{28}$$) + (-$$\frac{12}{35}$$).

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Ответ:

Решим примеры:

  1. a) $$-1\frac{1}{2} + (-2\frac{1}{2}) = -1\frac{1}{2} - 2\frac{1}{2} = -(1\frac{1}{2} + 2\frac{1}{2}) = - (1 + 2 + \frac{1}{2} + \frac{1}{2}) = - (3 + 1) = -4$$
  2. б) $$-4\frac{9}{14} + (-1\frac{1}{7}) = -4\frac{9}{14} - 1\frac{1}{7} = -(4\frac{9}{14} + 1\frac{1}{7}) = - (4 + 1 + \frac{9}{14} + \frac{1}{7}) = - (5 + \frac{9}{14} + \frac{1 \cdot 2}{7 \cdot 2}) = - (5 + \frac{9}{14} + \frac{2}{14}) = - (5 + \frac{11}{14}) = -5\frac{11}{14}$$
  3. в) $$-5\frac{7}{12} + (-2\frac{3}{4}) = -5\frac{7}{12} - 2\frac{3}{4} = -(5\frac{7}{12} + 2\frac{3}{4}) = - (5 + 2 + \frac{7}{12} + \frac{3}{4}) = -(7 + \frac{7}{12} + \frac{3 \cdot 3}{4 \cdot 3}) = -(7 + \frac{7}{12} + \frac{9}{12}) = -(7 + \frac{16}{12}) = -(7 + 1\frac{4}{12}) = -(8\frac{4}{12}) = -8\frac{1}{3}$$
  4. г) $$-3\frac{4}{9} + (-8\frac{5}{6}) = -3\frac{4}{9} - 8\frac{5}{6} = -(3\frac{4}{9} + 8\frac{5}{6}) = -(3 + 8 + \frac{4}{9} + \frac{5}{6}) = -(11 + \frac{4 \cdot 2}{9 \cdot 2} + \frac{5 \cdot 3}{6 \cdot 3}) = -(11 + \frac{8}{18} + \frac{15}{18}) = -(11 + \frac{23}{18}) = -(11 + 1\frac{5}{18}) = -12\frac{5}{18}$$
  5. д) $$-5\frac{12}{17} + (-\frac{15}{24}) + (-1\frac{3}{8}) + (-\frac{5}{17}) = -5\frac{12}{17} - \frac{5}{8} - 1\frac{3}{8} - \frac{5}{17} = -(5\frac{12}{17} + \frac{5}{8} + 1\frac{3}{8} + \frac{5}{17}) = -(5 + 1 + \frac{12}{17} + \frac{5}{17} + \frac{5}{8} + \frac{3}{8}) = -(6 + \frac{17}{17} + \frac{8}{8}) = -(6 + 1 + 1) = -8$$
  6. е) -$$\frac{9}{28} + (-4\frac{9}{35}) + (-2\frac{5}{28}) + (-\frac{12}{35}) = -\frac{9}{28} - 4\frac{9}{35} - 2\frac{5}{28} - \frac{12}{35} = -(\frac{9}{28} + 4\frac{9}{35} + 2\frac{5}{28} + \frac{12}{35}) = -(4 + 2 + \frac{9}{28} + \frac{5}{28} + \frac{9}{35} + \frac{12}{35}) = -(6 + \frac{14}{28} + \frac{21}{35}) = -(6 + \frac{1}{2} + \frac{3}{5}) = -(6 + \frac{1 \cdot 5}{2 \cdot 5} + \frac{3 \cdot 2}{5 \cdot 2}) = -(6 + \frac{5}{10} + \frac{6}{10}) = -(6 + \frac{11}{10}) = -(6 + 1\frac{1}{10}) = -7\frac{1}{10}$$

Ответ: a) -4; б) -5$$\frac{11}{14}$$; в) -8$$\frac{1}{3}$$; г) -12$$\frac{5}{18}$$; д) -8; е) -7$$\frac{1}{10}$$.

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