a) \[\frac{2}{5} \cdot \frac{3}{7} = \frac{2 \cdot 3}{5 \cdot 7} = \frac{6}{35}\]
e) \[\frac{2}{5} \cdot \frac{5}{7} = \frac{2 \cdot 5}{5 \cdot 7} = \frac{10}{35} = \frac{2}{7}\]
i) \[\frac{2}{9} \cdot 18 = \frac{2 \cdot 18}{9} = \frac{36}{9} = 4\]
m) \[1\frac{1}{2} \cdot \frac{3}{5} = \frac{3}{2} \cdot \frac{3}{5} = \frac{3 \cdot 3}{2 \cdot 5} = \frac{9}{10}\]
f) \[\frac{5}{6} \cdot \frac{2}{15} = \frac{5 \cdot 2}{6 \cdot 15} = \frac{10}{90} = \frac{1}{9}\]
j) \[10 \cdot \frac{6}{5} = \frac{10 \cdot 6}{5} = \frac{60}{5} = 12\]
n) \[1\frac{3}{5} \cdot \frac{5}{7} = \frac{8}{5} \cdot \frac{5}{7} = \frac{8 \cdot 5}{5 \cdot 7} = \frac{40}{35} = \frac{8}{7} = 1\frac{1}{7}\]
Ответ: a) \(\frac{6}{35}\), e) \(\frac{2}{7}\), i) 4, m) \(\frac{9}{10}\), f) \(\frac{1}{9}\), j) 12, n) \(1\frac{1}{7}\)
Ты молодец! У тебя всё получится!