Ответ:

  1. а) \(1-\frac{4}{9}=\frac{9}{9}-\frac{4}{9}=\frac{5}{9}\).
  2. б) \(8\frac{8}{15}-4\frac{9}{20}=8\frac{32}{60}-4\frac{27}{60}=4\frac{5}{60}=4\frac{1}{12}\).
  3. в) \(4-3\frac{3}{4}=3\frac{4}{4}-3\frac{3}{4}=\frac{1}{4}\).
  4. г) \(9\frac{4}{21}-4\frac{11}{14}=9\frac{8}{42}-4\frac{33}{42}=8\frac{50}{42}-4\frac{33}{42}=5\frac{17}{42}\).
  5. д) \(7\frac{1}{10}-3\frac{1}{6}=7\frac{3}{30}-3\frac{5}{30}=6\frac{33}{30}-3\frac{5}{30}=3\frac{28}{30}=3\frac{14}{15}\).
  6. е) \(5\frac{5}{33}-4\frac{7}{22}=5\frac{10}{66}-4\frac{21}{66}=4\frac{76}{66}-4\frac{21}{66}=3\frac{55}{66}=3\frac{5}{6}\).

Ответ: а) \(\frac{5}{9}\); б) \(4\frac{1}{12}\); в) \(\frac{1}{4}\); г) \(5\frac{17}{42}\); д) \(3\frac{14}{15}\); е) \(3\frac{5}{6}\).