Решение:

1. $$3\frac{1}{16} - \frac{1}{8} = 3\frac{1}{16} - \frac{2}{16} = 2\frac{17}{16} - \frac{2}{16} = 2\frac{15}{16}$$
2. $$7\frac{9}{20} - 5\frac{17}{30} = 7\frac{27}{60} - 5\frac{34}{60} = 6\frac{87}{60} - 5\frac{34}{60} = (6-5) + (\frac{87}{60} - \frac{34}{60}) = 1 + \frac{53}{60} = 1\frac{53}{60}$$
3. $$4\frac{2}{7} - 1\frac{4}{9} = 4\frac{18}{63} - 1\frac{28}{63} = 3\frac{81}{63} - 1\frac{28}{63} = (3-1) + (\frac{81}{63} - \frac{28}{63}) = 2 + \frac{53}{63} = 2\frac{53}{63}$$
4. $$8\frac{5}{36} - 1\frac{43}{108} = 8\frac{15}{108} - 1\frac{43}{108} = 7\frac{123}{108} - 1\frac{43}{108} = (7-1) + (\frac{123}{108} - \frac{43}{108}) = 6 + \frac{80}{108} = 6\frac{20}{27}$$
5. $$9\frac{7}{9} - 4\frac{5}{6} = 9\frac{14}{18} - 4\frac{15}{18} = 8\frac{32}{18} - 4\frac{15}{18} = (8-4) + (\frac{32}{18} - \frac{15}{18}) = 4 + \frac{17}{18} = 4\frac{17}{18}$$
6. $$6\frac{7}{32} - 2\frac{11}{48} = 6\frac{21}{96} - 2\frac{22}{96} = 5\frac{117}{96} - 2\frac{22}{96} = (5-2) + (\frac{117}{96} - \frac{22}{96}) = 3 + \frac{95}{96} = 3\frac{95}{96}$$