Решение:
а) $$8\frac{9}{11} - 3\frac{5}{11} = (8-3) + (\frac{9}{11} - \frac{5}{11}) = 5 + \frac{9-5}{11} = 5\frac{4}{11}$$
б) $$9 - \frac{5}{6} = 8\frac{6}{6} - \frac{5}{6} = 8\frac{6-5}{6} = 8\frac{1}{6}$$
в) $$8\frac{2}{7} - 3\frac{5}{7} = (8-3) + (\frac{2}{7} - \frac{5}{7}) = 5 - \frac{3}{7} = 4\frac{7}{7} - \frac{3}{7} = 4\frac{4}{7}$$
г) $$9 - 3\frac{5}{8} = (9-3) - \frac{5}{8} = 6 - \frac{5}{8} = 5\frac{8}{8} - \frac{5}{8} = 5\frac{3}{8}$$
д) $$6\frac{5}{8} - 4 = (6-4) + \frac{5}{8} = 2\frac{5}{8}$$
е) $$8\frac{3}{8} - 5\frac{3}{8} = (8-5) + (\frac{3}{8} - \frac{3}{8}) = 3 + 0 = 3$$
Ответ:
а) $$5\frac{4}{11}$$
б) $$8\frac{1}{6}$$
в) $$4\frac{4}{7}$$
г) $$5\frac{3}{8}$$
д) $$2\frac{5}{8}$$
е) $$3$$