Решение:
2 \( \frac{1}{7} \) = \( \frac{2 imes 7 + 1}{7} \) = \( \frac{15}{7} \)
4 \( \frac{6}{7} \) = \( \frac{4 imes 7 + 6}{7} \) = \( \frac{34}{7} \)
\( \frac{15}{7} \)a + \( \frac{34}{7} \)a = \( \frac{15+34}{7} \)a = \( \frac{49}{7} \)a
\( \frac{49}{7} \)a = 7a
Ответ: 7a