8) x² + x x² x - 1. 4 4 X

8) $$\frac{x^2+x}{4} \cdot \frac{x^2}{4} + \frac{x-1}{x} = \frac{x(x+1)x^2}{16} + \frac{x-1}{x} = \frac{x^3(x+1)}{16} + \frac{x-1}{x} = \frac{x^4(x+1) + 16(x-1)}{16x} = \frac{x^5 + x^4 + 16x - 16}{16x}$$

Ответ: $$\frac{x^5 + x^4 + 16x - 16}{16x}$$