\[ x^2 = 49 \]
\[ x = \pm \sqrt{49} \]
\[ x = \pm 7 \]
Ответ: x = 7, x = -7
\[ x(4x - 5) = 0 \]
\[ x = 0 \quad \text{или} \quad 4x - 5 = 0 \]
\[ 4x = 5 \]
\[ x = \frac{5}{4} = 1.25 \]
Ответ: x = 0, x = 1.25
\[ x_1 + x_2 = -1 \]
\[ x_1 \cdot x_2 = -56 \]
\[ x_1 = -8, \quad x_2 = 7 \]
Ответ: x = -8, x = 7
\[ 2x^2 - 9x + 4 = 0 \]
\[ D = (-9)^2 - 4 \cdot 2 \cdot 4 = 81 - 32 = 49 \]
\[ x = \frac{9 \pm \sqrt{49}}{2 \cdot 2} = \frac{9 \pm 7}{4} \]
\[ x_1 = \frac{9 + 7}{4} = \frac{16}{4} = 4 \]
\[ x_2 = \frac{9 - 7}{4} = \frac{2}{4} = 0.5 \]
Ответ: x = 4, x = 0.5
\[ 30x - 12 < 2x \]
\[ 30x - 2x < 12 \]
\[ 28x < 12 \]
\[ x < \frac{12}{28} \]
\[ x < \frac{3}{7} \]
Ответ: x < 3/7
\[ 3x - 15 > 7x \]
\[ -15 > 4x \]
\[ x < -\frac{15}{4} \]
\[ x < -3.75 \]
Ответ: x < -3.75
\[ -4x + 12 \le 3x \]
\[ 12 \le 7x \]
\[ x \ge \frac{12}{7} \]
Ответ: x ≥ 12/7
\[ 2x + 10 \ge x + 4 \]
\[ 2x - x \ge 4 - 10 \]
\[ x \ge -6 \]
Ответ: x ≥ -6