Предмет: Математика. Класс: 6-7.
Решаем уравнения.
1) \(x + 0.75 + \frac{5}{8} = 2.125\)
\(x + 0.75 + 0.625 = 2.125\)
\(x + 1.375 = 2.125\)
\(x = 2.125 - 1.375\)
\(x = 0.75\)
2) \(x + \frac{7}{12} = \frac{1}{3} + 0.5 \cdot 1\frac{2}{3}\)
\(x + \frac{7}{12} = \frac{1}{3} + \frac{1}{2} \cdot \frac{5}{3}\)
\(x + \frac{7}{12} = \frac{1}{3} + \frac{5}{6}\)
\(x + \frac{7}{12} = \frac{2}{6} + \frac{5}{6}\)
\(x + \frac{7}{12} = \frac{7}{6}\)
\(x = \frac{7}{6} - \frac{7}{12}\)
\(x = \frac{14}{12} - \frac{7}{12}\)
\(x = \frac{7}{12}\)
3) \(1\frac{3}{4} - (0.7 - 2\frac{1}{2} \cdot x) = 1.17\)
\(1.75 - (0.7 - 2.5x) = 1.17\)
\(1.75 - 0.7 + 2.5x = 1.17\)
\(1.05 + 2.5x = 1.17\)
\(2.5x = 1.17 - 1.05\)
\(2.5x = 0.12\)
\(x = \frac{0.12}{2.5}\)
\(x = 0.048\)
4) \((2.4 \cdot x + 1\frac{2}{3}) - \frac{5}{6} = 5\frac{19}{30}\)
\((2.4x + \frac{5}{3}) - \frac{5}{6} = \frac{169}{30}\)
\(2.4x + \frac{5}{3} = \frac{169}{30} + \frac{5}{6}\)
\(2.4x + \frac{5}{3} = \frac{169}{30} + \frac{25}{30}\)
\(2.4x + \frac{5}{3} = \frac{194}{30}\)
\(2.4x = \frac{194}{30} - \frac{5}{3}\)
\(2.4x = \frac{194}{30} - \frac{50}{30}\)
\(2.4x = \frac{144}{30}\)
\(2.4x = \frac{24}{5}\)
\(x = \frac{24}{5} : 2.4\)
\(x = \frac{24}{5} : \frac{12}{5}\)
\(x = \frac{24}{5} \cdot \frac{5}{12}\)
\(x = 2\)
Ответ: 1) x = 0.75; 2) x = 7/12; 3) x = 0.048; 4) x = 2
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