6) 2x + 7y + 14 + xy; б) За - 3m - ay + my. в) ау - 12bx + 3ax - 4by; r) a²b² + ab + abc + c; y + by + cy; - c + abc - ca²b²; б) у 12: + 12 = x² + 3x + 4x + 12 = 3)+4(x + 3) = (x + 3)(x + 4). x² - 8x + 15.

Решение:

6) 2x + 7y + 14 + xy \[2x + 7y + 14 + xy = (2x + xy) + (7y + 14) = x(2 + y) + 7(y + 2) = (x + 7)(y + 2).\] б) За - 3m - ay + my \[3a - 3m - ay + my = (3a - 3m) + (-ay + my) = 3(a - m) - y(a - m) = (3 - y)(a - m).\] в) ау - 12bx + 3ax - 4by \[ay - 12bx + 3ax - 4by = (ay + 3ax) + (-12bx - 4by) = a(y + 3x) - 4b(3x + y) = (a - 4b)(y + 3x).\] r) a²b² + ab + abc + c \[a^2b^2 + ab + abc + c = (a^2b^2 + ab) + (abc + c) = ab(ab + 1) + c(ab + 1) = (ab + c)(ab + 1).\] y + by + cy \[y + by + cy = y(1 + b + c).\] - c + abc - ca²b² \[-c + abc - ca^2b^2 = -c(1 - ab + a^2b^2).\] б) у^{n + 3} - y^-1 + yⁿ⁺¹ \[y^{n + 3} - y^{-1} + y^{n+1} = y^{-1}(y^{n+4} - 1 + y^{n+2}).\] 12: x² + 3x + 4x + 12 \[x^2 + 3x + 4x + 12 = (x + 3)(x + 4).\] 3)+4(x + 3) = (x + 3)(x + 4). x² - 8x + 15 \[x^2 - 8x + 15 = (x - 3)(x - 5).\]