\[\begin{cases} 3x + 2y = 10 \\ 4x + y = 15 \\ \end{cases}\]
\[\begin{cases} 3x + 2y = 10 \\ -2 \cdot (4x + y) = -2 \cdot 15 \\ \end{cases}\]
\[\begin{cases} 3x + 2y = 10 \\ \textbf{-8}x - 2y = \textbf{-30} \\ \end{cases}\]
\[\begin{cases} 3x + 2y = 10 \\ \textbf{-8}x - 2y = \textbf{-30} \\ \end{cases}\]
\[\begin{aligned} (3x + 2y) + (\textbf{-8}x - 2y) &= 10 + (\textbf{-30}) \\ 3x + 2y - 8x - 2y &= -20 \\ \textbf{-5}x &= \textbf{-20} \\ \end{aligned}\]
\[\begin{aligned} -5x &= -20 \\ x &= \frac{-20}{-5} \\ x &= \textbf{4} \end{aligned}\]
\[\begin{aligned} 4 \cdot 4 + y &= 15 \\ 16 + y &= 15 \\ y &= 15 - 16 \\ y &= \textbf{-1} \end{aligned}\]
\[\begin{cases} x = \textbf{4} \\ y = \textbf{-1} \end{cases}\]
Ответ: x = 4; y = -1