7y-49 y-7 г) -:-. y² +7y y² + 14y+49

г) $$\frac{7y-49}{y^2+7y} : \frac{y-7}{y^2+14y+49} = \frac{7(y-7)}{y(y+7)} : \frac{y-7}{(y+7)^2} = \frac{7(y-7)}{y(y+7)} \cdot \frac{(y+7)^2}{y-7} = \frac{7(y-7)(y+7)(y+7)}{y(y+7)(y-7)} = \frac{7(y+7)}{y}$$

Ответ: $$\frac{7(y+7)}{y}$$