з) \frac{2+\frac{1}{3}}{\frac{1}{2}} + \frac{\frac{1}{2}}{2-\frac{1}{3}} =

з) Решим пример:

$$\frac{2+\frac{1}{3}}{\frac{1}{2}} + \frac{\frac{1}{2}}{2-\frac{1}{3}} = \frac{\frac{6}{3}+\frac{1}{3}}{\frac{1}{2}} + \frac{\frac{1}{2}}{\frac{6}{3}-\frac{1}{3}} = \frac{\frac{7}{3}}{\frac{1}{2}} + \frac{\frac{1}{2}}{\frac{5}{3}} = \frac{7}{3} \cdot \frac{2}{1} + \frac{1}{2} \cdot \frac{3}{5} = \frac{14}{3} + \frac{3}{10} = \frac{140}{30} + \frac{9}{30} = \frac{149}{30} = 4\frac{29}{30}$$

Ответ: $$4\frac{29}{30}$$