Ответ: Решение математических выражений
Краткое пояснение: Необходимо выполнить действия с дробями и степенями, упрощая выражения.
Задание 1
1) \[\frac{(1 \frac{7}{10} + \frac{1}{20})}{\frac{2}{15}} = \frac{(\frac{17}{10} + \frac{1}{20})}{\frac{2}{15}} = \frac{(\frac{34}{20} + \frac{1}{20})}{\frac{2}{15}} = \frac{\frac{35}{20}}{\frac{2}{15}} = \frac{35}{20} \cdot \frac{15}{2} = \frac{35 \cdot 3}{4 \cdot 2} = \frac{105}{8} = 13 \frac{1}{8}\]
4) \[\frac{(10 \frac{15}{13} - \frac{26}{4})}{5} = \frac{(\frac{145}{13} - \frac{13}{2})}{5} = \frac{(\frac{290 - 169}{26})}{5} = \frac{\frac{121}{26}}{5} = \frac{121}{26} \cdot \frac{1}{5} = \frac{121}{130}\]
7) \[(\frac{3}{4} - \frac{1}{6}) \cdot 3 = (\frac{9}{12} - \frac{2}{12}) \cdot 3 = \frac{7}{12} \cdot 3 = \frac{7}{4} = 1 \frac{3}{4}\]
10) \[(\frac{2}{20} + \frac{7}{30}) \cdot 15 = (\frac{1}{10} + \frac{7}{30}) \cdot 15 = (\frac{3}{30} + \frac{7}{30}) \cdot 15 = \frac{10}{30} \cdot 15 = \frac{1}{3} \cdot 15 = 5\]
2) \[(\frac{5}{22} + \frac{8}{11}) \cdot \frac{11}{5} = (\frac{5}{22} + \frac{16}{22}) \cdot \frac{11}{5} = \frac{21}{22} \cdot \frac{11}{5} = \frac{21}{2} \cdot \frac{1}{5} = \frac{21}{10} = 2 \frac{1}{10}\]
5) \[(\frac{17}{26} + \frac{11}{13}) \cdot \frac{17}{6} = (\frac{17}{26} + \frac{22}{26}) \cdot \frac{17}{6} = \frac{39}{26} \cdot \frac{17}{6} = \frac{3}{2} \cdot \frac{17}{6} = \frac{17}{4} = 4 \frac{1}{4}\]
8) \[(\frac{2}{5} + \frac{13}{15}) \cdot 6 = (\frac{6}{15} + \frac{13}{15}) \cdot 6 = \frac{19}{15} \cdot 6 = \frac{19}{5} \cdot 2 = \frac{38}{5} = 7 \frac{3}{5}\]
11) \[(\frac{9}{10} - \frac{7}{15}) \cdot 3 = (\frac{27}{30} - \frac{14}{30}) \cdot 3 = \frac{13}{30} \cdot 3 = \frac{13}{10} = 1 \frac{3}{10}\]
3) \[(\frac{5}{26} - \frac{3}{25}) \cdot \frac{13}{2} = (\frac{125}{650} - \frac{78}{650}) \cdot \frac{13}{2} = \frac{47}{650} \cdot \frac{13}{2} = \frac{47}{50} \cdot \frac{1}{2} = \frac{47}{100}\]
6) \[(\frac{11}{12} - \frac{11}{20}) \cdot \frac{15}{8} = (\frac{55}{60} - \frac{33}{60}) \cdot \frac{15}{8} = \frac{22}{60} \cdot \frac{15}{8} = \frac{11}{30} \cdot \frac{15}{8} = \frac{11}{2} \cdot \frac{1}{8} = \frac{11}{16}\]
9) \[(\frac{3}{8} - \frac{1}{20}) \cdot 10 = (\frac{15}{40} - \frac{2}{40}) \cdot 10 = \frac{13}{40} \cdot 10 = \frac{13}{4} = 3 \frac{1}{4}\]
12) \[(\frac{1}{6} + \frac{1}{4}) \cdot 9 = (\frac{2}{12} + \frac{3}{12}) \cdot 9 = \frac{5}{12} \cdot 9 = \frac{5}{4} \cdot 3 = \frac{15}{4} = 3 \frac{3}{4}\]
Задание 2
1) \[(\frac{9}{16} + 2\frac{3}{8}) \cdot 4 = (\frac{9}{16} + \frac{19}{8}) \cdot 4 = (\frac{9}{16} + \frac{38}{16}) \cdot 4 = \frac{47}{16} \cdot 4 = \frac{47}{4} = 11 \frac{3}{4}\]
5) \[(1\frac{3}{4} + 2\frac{4}{5}) \cdot 30 = (\frac{7}{4} + \frac{14}{5}) \cdot 30 = (\frac{35}{20} + \frac{56}{20}) \cdot 30 = \frac{91}{20} \cdot 30 = \frac{91}{2} \cdot 3 = \frac{273}{2} = 136 \frac{1}{2}\]
9) \[4\frac{7}{8} \cdot (2\frac{3}{4} + 1\frac{10}{19}) = \frac{39}{8} \cdot (\frac{11}{4} + \frac{29}{19}) = \frac{39}{8} \cdot (\frac{209}{76} + \frac{116}{76}) = \frac{39}{8} \cdot \frac{325}{76} = \frac{39 \cdot 325}{8 \cdot 76} = \frac{12675}{608} = 20 \frac{515}{608}\]
2) \[(\frac{4}{9} - 3\frac{1}{15}) \cdot 9 = (\frac{4}{9} - \frac{46}{15}) \cdot 9 = (\frac{20}{45} - \frac{138}{45}) \cdot 9 = \frac{-118}{45} \cdot 9 = \frac{-118}{5} = -23 \frac{3}{5}\]
6) \[(1\frac{1}{13} - 2\frac{3}{4}) \cdot 26 = (\frac{14}{13} - \frac{11}{4}) \cdot 26 = (\frac{56}{52} - \frac{143}{52}) \cdot 26 = \frac{-87}{52} \cdot 26 = \frac{-87}{2} = -43 \frac{1}{2}\]
10) \[1\frac{1}{12} \cdot (1\frac{13}{18} - 2\frac{5}{9}) = \frac{13}{12} \cdot (\frac{31}{18} - \frac{23}{9}) = \frac{13}{12} \cdot (\frac{31}{18} - \frac{46}{18}) = \frac{13}{12} \cdot \frac{-15}{18} = \frac{13}{4} \cdot \frac{-5}{6} = \frac{-65}{24} = -2 \frac{17}{24}\]