\(\left(3\frac{2}{3} + 1\frac{3}{4}\right) : \left(6\frac{7}{12} - 2\frac{1}{4}\right) \cdot \frac{4}{5} = \)
\(\left(\frac{11}{3} + \frac{7}{4}\right) : \left(\frac{79}{12} - \frac{9}{4}\right) \cdot \frac{4}{5} = \)
\(\left(\frac{44}{12} + \frac{21}{12}\right) : \left(\frac{79}{12} - \frac{27}{12}\right) \cdot \frac{4}{5} = \)
\(\frac{65}{12} : \frac{52}{12} \cdot \frac{4}{5} = \)
\(\frac{65}{12} \cdot \frac{12}{52} \cdot \frac{4}{5} = \)
\(\frac{65 \cdot 12 \cdot 4}{12 \cdot 52 \cdot 5} = \)
\(\frac{65 \cdot 4}{52 \cdot 5} = \)
\(\frac{260}{260} = 1\)
Ответ: 1