Задание 2. Найдите значение выражения: 1) (\frac{9}{16} + 2\frac{3}{8}) \cdot 4 2) (\frac{4}{9} - 3\frac{1}{15}) \cdot 9 3) (2\frac{3}{4} + 2\frac{1}{5}) \cdot 16 4) (\frac{11}{16} - 3\frac{7}{8}) \cdot 4 5) (1\frac{3}{4} + 2\frac{4}{5}) \cdot 30 6) (\frac{1}{13} - 2\frac{3}{4}) \cdot 26 7) 1\frac{8}{17} : (\frac{12}{17} + 2\frac{7}{11}) 8) 3\frac{4}{9} : (\frac{5}{9} - \frac{4}{7}) 9) 4\frac{7}{8} : (2\frac{3}{4} + 1\frac{10}{19}) 10) 1\frac{1}{12} : (\frac{13}{18} - 2\frac{5}{9}) 11) 3\frac{1}{2} : (1\frac{4}{15} + 2\frac{9}{10}) 12) 4\frac{1}{4} : (2\frac{7}{10} - 3\frac{1}{8})

Решение: 1) (\frac{9}{16} + 2\frac{3}{8}) \cdot 4 = (\frac{9}{16} + \frac{19}{8}) \cdot 4 = (\frac{9 + 38}{16}) \cdot 4 = \frac{47}{16} \cdot 4 = \frac{47}{4} = 11.75 2) (\frac{4}{9} - 3\frac{1}{15}) \cdot 9 = (\frac{4}{9} - \frac{46}{15}) \cdot 9 = (\frac{20 - 138}{45}) \cdot 9 = \frac{-118}{45} \cdot 9 = \frac{-118}{5} = -23.6 3) (2\frac{3}{4} + 2\frac{1}{5}) \cdot 16 = (\frac{11}{4} + \frac{11}{5}) \cdot 16 = (\frac{55 + 44}{20}) \cdot 16 = \frac{99}{20} \cdot 16 = \frac{99 \cdot 4}{5} = \frac{396}{5} = 79.2 4) (\frac{11}{16} - 3\frac{7}{8}) \cdot 4 = (\frac{11}{16} - \frac{31}{8}) \cdot 4 = (\frac{11 - 62}{16}) \cdot 4 = \frac{-51}{16} \cdot 4 = \frac{-51}{4} = -12.75 5) (1\frac{3}{4} + 2\frac{4}{5}) \cdot 30 = (\frac{7}{4} + \frac{14}{5}) \cdot 30 = (\frac{35 + 56}{20}) \cdot 30 = \frac{91}{20} \cdot 30 = \frac{91 \cdot 3}{2} = \frac{273}{2} = 136.5 6) (\frac{1}{13} - 2\frac{3}{4}) \cdot 26 = (\frac{1}{13} - \frac{11}{4}) \cdot 26 = (\frac{4 - 143}{52}) \cdot 26 = \frac{-139}{52} \cdot 26 = \frac{-139}{2} = -69.5 7) 1\frac{8}{17} : (\frac{12}{17} + 2\frac{7}{11}) = \frac{25}{17} : (\frac{12}{17} + \frac{29}{11}) = \frac{25}{17} : (\frac{132 + 493}{187}) = \frac{25}{17} : \frac{625}{187} = \frac{25}{17} \cdot \frac{187}{625} = \frac{1}{1} \cdot \frac{11}{25} = \frac{11}{25} = 0.44 8) 3\frac{4}{9} : (\frac{5}{9} - \frac{4}{7}) = \frac{31}{9} : (\frac{35 - 36}{63}) = \frac{31}{9} : \frac{-1}{63} = \frac{31}{9} \cdot (-63) = 31 \cdot (-7) = -217 9) 4\frac{7}{8} : (2\frac{3}{4} + 1\frac{10}{19}) = \frac{39}{8} : (\frac{11}{4} + \frac{29}{19}) = \frac{39}{8} : (\frac{209 + 116}{76}) = \frac{39}{8} : \frac{325}{76} = \frac{39}{8} \cdot \frac{76}{325} = \frac{39 \cdot 19}{2 \cdot 325} = \frac{39 \cdot 19}{650} = \frac{741}{650} = 1.14 10) 1\frac{1}{12} : (\frac{13}{18} - 2\frac{5}{9}) = \frac{13}{12} : (\frac{13}{18} - \frac{23}{9}) = \frac{13}{12} : (\frac{13 - 46}{18}) = \frac{13}{12} : (\frac{-33}{18}) = \frac{13}{12} \cdot \frac{-18}{33} = \frac{13}{2} \cdot \frac{-3}{33} = \frac{13}{2} \cdot \frac{-1}{11} = \frac{-13}{22} = -0.59 11) 3\frac{1}{2} : (1\frac{4}{15} + 2\frac{9}{10}) = \frac{7}{2} : (\frac{19}{15} + \frac{29}{10}) = \frac{7}{2} : (\frac{38 + 87}{30}) = \frac{7}{2} : \frac{125}{30} = \frac{7}{2} \cdot \frac{30}{125} = \frac{7}{1} \cdot \frac{15}{125} = \frac{105}{125} = \frac{21}{25} = 0.84 12) 4\frac{1}{4} : (2\frac{7}{10} - 3\frac{1}{8}) = \frac{17}{4} : (\frac{27}{10} - \frac{25}{8}) = \frac{17}{4} : (\frac{108 - 125}{40}) = \frac{17}{4} : \frac{-17}{40} = \frac{17}{4} \cdot \frac{-40}{17} = -10