Задание 2. Переведем смешанные числа в неправильные дроби.
- $$6\frac{3}{5} = \frac{6 \cdot 5 + 3}{5} = \frac{30 + 3}{5} = \frac{33}{5}$$
- $$1\frac{5}{6} = \frac{1 \cdot 6 + 5}{6} = \frac{6 + 5}{6} = \frac{11}{6}$$
- $$3\frac{9}{11} = \frac{3 \cdot 11 + 9}{11} = \frac{33 + 9}{11} = \frac{42}{11}$$
- $$11\frac{2}{15} = \frac{11 \cdot 15 + 2}{15} = \frac{165 + 2}{15} = \frac{167}{15}$$
- $$10\frac{2}{19} = \frac{10 \cdot 19 + 2}{19} = \frac{190 + 2}{19} = \frac{192}{19}$$
- $$4\frac{2}{9} = \frac{4 \cdot 9 + 2}{9} = \frac{36 + 2}{9} = \frac{38}{9}$$
- $$8\frac{1}{13} = \frac{8 \cdot 13 + 1}{13} = \frac{104 + 1}{13} = \frac{105}{13}$$
- $$7\frac{4}{5} = \frac{7 \cdot 5 + 4}{5} = \frac{35 + 4}{5} = \frac{39}{5}$$
- $$6\frac{4}{23} = \frac{6 \cdot 23 + 4}{23} = \frac{138 + 4}{23} = \frac{142}{23}$$
- $$3\frac{23}{15} = \frac{3 \cdot 15 + 23}{15} = \frac{45 + 23}{15} = \frac{68}{15}$$
Ответ: 1) $$\frac{33}{5}$$, 2) $$\frac{11}{6}$$, 3) $$\frac{42}{11}$$, 4) $$\frac{167}{15}$$, 5) $$\frac{192}{19}$$, 6) $$\frac{38}{9}$$, 7) $$\frac{105}{13}$$, 8) $$\frac{39}{5}$$, 9) $$\frac{142}{23}$$, 10) $$\frac{68}{15}$$