Задание 97. Представьте обыкновенную дробь в виде десятичной и выполните действие. 1)+(-1,7) = 0,4+(-1,7) = =-(1,7-0,4)= -1,3 2)+(-2,1) = 3)-+0,75 = 1 4)-+1,3 4 5)-2,5+= 6) 0,26+ 3 7)-1,2+- -1,2+25= 8)+(-0,18) = 9) -20+5,36 = 10)-1+0,45 = Задание 98. Представьте десятичную дробь в виде обыкновенной и выполните действие. 2 2 9 20 10,3+(-3)=1+(-3)=30+(-3) = 6)2+(-8,9)= 20 9 30 30 11 30 2) 0,4+(-1)= 3)+(-0,7) = 7)-1/+0,7 = 8) 8+(-7,3) = 2 4)-+1,3= 11 5)-1,7+= 9)-2,4+3= 10) 6,9+(-4)=

Давай разберем по порядку. Задание 97. 1) \[\frac{2}{5} + (-1.7) = 0.4 - 1.7 = -1.3\] 2) \[\frac{3}{5} + (-2.1) = 0.6 - 2.1 = -1.5\] 3) \[-\frac{1}{5} + 0.75 = -0.2 + 0.75 = 0.55\] 4) \[-\frac{1}{4} + 1.3 = -0.25 + 1.3 = 1.05\] 5) \[-2.5 + \frac{3}{4} = -2.5 + 0.75 = -1.75\] 6) \[0.26 + (-\frac{11}{20}) = 0.26 - 0.55 = -0.29\] 7) \[-1.2 + \frac{3}{25} = -1.2 + 0.12 = -1.08\] 8) \[-\frac{3}{50} + (-0.18) = -0.06 - 0.18 = -0.24\] 9) \[-\frac{7}{20} + 5.36 = -0.35 + 5.36 = 5.01\] 10) \[-1\frac{4}{5} + 0.45 = -1.8 + 0.45 = -1.35\] Задание 98. 1) \[0.3 + (-\frac{2}{3}) = \frac{3}{10} - \frac{2}{3} = \frac{9}{30} - \frac{20}{30} = -\frac{11}{30}\] 2) \[0.4 + (-\frac{1}{6}) = \frac{4}{10} - \frac{1}{6} = \frac{24}{60} - \frac{10}{60} = \frac{14}{60} = \frac{7}{30}\] 3) \[-\frac{2}{7} + (-0.7) = -\frac{2}{7} - \frac{7}{10} = -\frac{20}{70} - \frac{49}{70} = -\frac{69}{70}\] 4) \[-\frac{2}{11} + 1.3 = -\frac{2}{11} + \frac{13}{10} = -\frac{20}{110} + \frac{143}{110} = \frac{123}{110} = 1\frac{13}{110}\] 5) \[-1.7 + \frac{4}{9} = -\frac{17}{10} + \frac{4}{9} = -\frac{153}{90} + \frac{40}{90} = -\frac{113}{90} = -1\frac{23}{90}\] 6) \[2\frac{8}{11} + (-3.9) = \frac{30}{11} - \frac{39}{10} = \frac{300}{110} - \frac{429}{110} = -\frac{129}{110} = -1\frac{19}{110}\] 7) \[-1\frac{5}{7} + 0.7 = -\frac{12}{7} + \frac{7}{10} = -\frac{120}{70} + \frac{49}{70} = -\frac{71}{70} = -1\frac{1}{70}\] 8) \[8\frac{1}{3} + (-7.3) = \frac{25}{3} - \frac{73}{10} = \frac{250}{30} - \frac{219}{30} = \frac{31}{30} = 1\frac{1}{30}\] 9) \[-2.4 + 3\frac{1}{6} = -\frac{24}{10} + \frac{19}{6} = -\frac{144}{60} + \frac{190}{60} = \frac{46}{60} = \frac{23}{30}\] 10) \[6.9 + (-4\frac{7}{9}) = \frac{69}{10} - \frac{43}{9} = \frac{621}{90} - \frac{430}{90} = \frac{191}{90} = 2\frac{11}{90}\]

Ответ: Решения выше.