\[1 \frac{3}{8} = \frac{1 \cdot 8 + 3}{8} = \frac{11}{8}\]
\[\frac{11}{8} : \frac{7}{1} = \frac{11}{8} \cdot \frac{1}{7} = \frac{11}{56}\]
\[5 \frac{5}{24} : 10 = \frac{5 \cdot 24 + 5}{24} : 10 = \frac{125}{24} : 10 = \frac{125}{24} \cdot \frac{1}{10} = \frac{25}{24} \cdot \frac{1}{2} = \frac{25}{48}\]
\[4 \frac{1}{15} : 3 = \frac{4 \cdot 15 + 1}{15} : 3 = \frac{61}{15} : 3 = \frac{61}{15} \cdot \frac{1}{3} = \frac{61}{45}\]
\[4 \frac{2}{9} : 27 = \frac{4 \cdot 9 + 2}{9} : 27 = \frac{38}{9} : 27 = \frac{38}{9} \cdot \frac{1}{27} = \frac{38}{243}\]
\[8 \frac{4}{25} : 15 = \frac{8 \cdot 25 + 4}{25} : 15 = \frac{204}{25} : 15 = \frac{204}{25} \cdot \frac{1}{15} = \frac{68}{25} \cdot \frac{1}{5} = \frac{68}{125}\]
\[10 \frac{10}{17} : 5 = \frac{10 \cdot 17 + 10}{17} : 5 = \frac{180}{17} : 5 = \frac{180}{17} \cdot \frac{1}{5} = \frac{36}{17} \cdot \frac{1}{1} = \frac{36}{17}\]
\[5 : 7 \frac{1}{2} = 5 : \frac{7 \cdot 2 + 1}{2} = 5 : \frac{15}{2} = 5 \cdot \frac{2}{15} = \frac{1}{1} \cdot \frac{2}{3} = \frac{2}{3}\]
\[1 \frac{5}{18} : 15 = \frac{1 \cdot 18 + 5}{18} : 15 = \frac{23}{18} : 15 = \frac{23}{18} \cdot \frac{1}{15} = \frac{23}{270}\]
\[21 \cdot (\frac{13}{24} - \frac{7}{12} + \frac{1}{6}) = 21 \cdot (\frac{13}{24} - \frac{14}{24} + \frac{4}{24}) = 21 \cdot \frac{13 - 14 + 4}{24} = 21 \cdot \frac{3}{24} = \frac{21}{1} \cdot \frac{1}{8} = \frac{21}{8} = 2 \frac{5}{8}\]
\[\frac{29}{7} : (\frac{2}{7} + \frac{3}{4}) = \frac{29}{7} : (\frac{8}{28} + \frac{21}{28}) = \frac{29}{7} : \frac{29}{28} = \frac{29}{7} \cdot \frac{28}{29} = \frac{1}{1} \cdot \frac{4}{1} = 4\]
\[3 : 1\frac{1}{2} + 5 : 1\frac{1}{4} = 3 : \frac{3}{2} + 5 : \frac{5}{4} = 3 \cdot \frac{2}{3} + 5 \cdot \frac{4}{5} = 2 + 4 = 6\]
\[(2 \frac{1}{16} - 1 \frac{1}{14}) \cdot 28 = (\frac{33}{16} - \frac{15}{14}) \cdot 28 = (\frac{33 \cdot 7}{16 \cdot 7} - \frac{15 \cdot 8}{14 \cdot 8}) \cdot 28 = (\frac{231}{112} - \frac{120}{112}) \cdot 28 = \frac{111}{112} \cdot 28 = \frac{111}{4} = 27 \frac{3}{4}\]
\[13 \frac{2}{5} + 11 \frac{1}{5} : 9 \frac{1}{3} = \frac{67}{5} + \frac{56}{5} : \frac{28}{3} = \frac{67}{5} + \frac{56}{5} \cdot \frac{3}{28} = \frac{67}{5} + \frac{2}{5} \cdot \frac{3}{1} = \frac{67}{5} + \frac{6}{5} = \frac{73}{5} = 14 \frac{3}{5}\]
\[4 \frac{1}{2} - 5 \frac{1}{10} : \frac{2}{3} = \frac{9}{2} - \frac{51}{10} : \frac{2}{3} = \frac{9}{2} - \frac{51}{10} \cdot \frac{3}{2} = \frac{9}{2} - \frac{153}{20} = \frac{90}{20} - \frac{153}{20} = - \frac{63}{20} = -3 \frac{3}{20}\]
Ответ: Решения выше